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anonymous

  • one year ago

decide whether the equation is a trigonometric identity. sin^2(x)csc^2(x)=sin^2(x)+cos^2(x)

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  1. zzr0ck3r
    • one year ago
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    What do we know that \(\cos^2(x)+\sin^2(x)=?\)

  2. zzr0ck3r
    • one year ago
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    @Reid448

  3. anonymous
    • one year ago
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    1

  4. anonymous
    • one year ago
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    1

  5. zzr0ck3r
    • one year ago
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    and \[\sin^2(x)*\csc^2(x)= \sin^2(x) * \frac{1}{\sin^2(x)}=?\]

  6. anonymous
    • one year ago
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    and \[\sin ^{2}=\frac{ 1-\cos2x }{ 2 }\]

  7. anonymous
    • one year ago
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    what you said also equals 1 so that makes this an identity

  8. anonymous
    • one year ago
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    thanks very much

  9. dinamix
    • one year ago
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    @zzr0ck3r i want ask u question how proof it sin^2(x) + cos^2(x) to---> sin^2(x) csc^2(x) cuz its relation equivalent

  10. zzr0ck3r
    • one year ago
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    ?

  11. dinamix
    • one year ago
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    u understand my question or no ?

  12. zzr0ck3r
    • one year ago
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    I don't think so.

  13. dinamix
    • one year ago
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    i mean u proof it from one side only

  14. zzr0ck3r
    • one year ago
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    we showed both sides equal 1

  15. zzr0ck3r
    • one year ago
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    you understand @dinamix

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