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wintersuntime

  • one year ago

Can someone be nice enough to help me please ?

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  1. anonymous
    • one year ago
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    why not?

  2. anonymous
    • one year ago
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    gotta ask though...

  3. wintersuntime
    • one year ago
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    I'll post the question

  4. wintersuntime
    • one year ago
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    It's page 8 3.2

  5. wintersuntime
    • one year ago
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    It's only this question -> Set Topic: Evaluating Equations Evaluate the following equations when x = { 1, 2, 3, 4, 5 }. Organize your inputs and outputs into a table of values for each equation. Let x be the input and y be the output.

  6. anonymous
    • one year ago
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    is the the \(4^x\) one?

  7. wintersuntime
    • one year ago
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    yes with the table

  8. DanJS
    • one year ago
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    ha, thanks for th ebook

  9. wintersuntime
    • one year ago
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    I have to answer those question 5. 6. 7. 8.

  10. anonymous
    • one year ago
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    ok in the first column put \( 1, 2, 3, 4, 5\) in the second put \(4, 4^2, 4^3, 4^4, 4^5 \) or rather what you get when you compute those numbers

  11. anonymous
    • one year ago
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    |dw:1441160033833:dw|

  12. anonymous
    • one year ago
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    make yours look neater

  13. wintersuntime
    • one year ago
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    That for question 5. right so its multipliying right

  14. anonymous
    • one year ago
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    it is raising to powers, not multiplying or "multiplying by itself x times"

  15. wintersuntime
    • one year ago
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    oh

  16. anonymous
    • one year ago
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    for example \(4^3=4\times 4\times 4=64\) not \(12\)

  17. wintersuntime
    • one year ago
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    Can you help me with the other question please

  18. wintersuntime
    • one year ago
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    @satellite73

  19. anonymous
    • one year ago
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    what is the quesiton?

  20. anonymous
    • one year ago
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    you mean the next one \((-3)^x\)?

  21. wintersuntime
    • one year ago
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    yes

  22. anonymous
    • one year ago
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    they are all the same idea replace x by 1, 2, 3, 4, 5 and see what you get

  23. wintersuntime
    • one year ago
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    |dw:1441161271918:dw|

  24. anonymous
    • one year ago
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    \(x=1,y=(3)^1=-3\) \(x=2,y=(-3)^2=9\) etc

  25. wintersuntime
    • one year ago
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    like that ?

  26. anonymous
    • one year ago
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    yup!

  27. wintersuntime
    • one year ago
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    yay

  28. anonymous
    • one year ago
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    yay indeed!

  29. wintersuntime
    • one year ago
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    for the next one is it the same

  30. anonymous
    • one year ago
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    for the next one it is not the same

  31. wintersuntime
    • one year ago
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    but they are all negative

  32. anonymous
    • one year ago
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    for the next one all the answers are negative yeah, what you said

  33. anonymous
    • one year ago
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    the last one is the easiest

  34. wintersuntime
    • one year ago
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    and for the next one is it the same idea

  35. anonymous
    • one year ago
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    10,100,1000,10000,10,000

  36. wintersuntime
    • one year ago
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    that was easy

  37. anonymous
    • one year ago
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    now i have a question what is that a picture of?

  38. wintersuntime
    • one year ago
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    what picture ?

  39. wintersuntime
    • one year ago
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    My profile pic

  40. anonymous
    • one year ago
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    yeah that one

  41. wintersuntime
    • one year ago
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    It's a band from of mice and men

  42. wintersuntime
    • one year ago
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    Of Mice & Men - Second and Sebring (Official Music Video)

  43. anonymous
    • one year ago
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    ooh

  44. wintersuntime
    • one year ago
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    https://www.youtube.com/watch?v=qSeiG6qMhaI

  45. wintersuntime
    • one year ago
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    you should listen to them they are really good

  46. wintersuntime
    • one year ago
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    hey I'm sorry to bother you but can you help me on 6 question if you can ?

  47. anonymous
    • one year ago
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    ok

  48. anonymous
    • one year ago
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    sure

  49. anonymous
    • one year ago
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    if i can

  50. wintersuntime
    • one year ago
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    okay

  51. wintersuntime
    • one year ago
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    It's on page 9

  52. anonymous
    • one year ago
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    on page 9 i see a bunch of equations, but no number 6

  53. wintersuntime
    • one year ago
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    yes its the equations

  54. anonymous
    • one year ago
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    \[3 x − 1 = 2(x + 3) \]

  55. anonymous
    • one year ago
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    like that one?

  56. wintersuntime
    • one year ago
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    yes

  57. anonymous
    • one year ago
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    distribute first

  58. anonymous
    • one year ago
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    \[3x-1=2x+6\]

  59. anonymous
    • one year ago
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    subtract \(2x\) from both sides \[x-1=6\]

  60. anonymous
    • one year ago
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    then add 1 \[x=7\]

  61. anonymous
    • one year ago
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    you got that?

  62. wintersuntime
    • one year ago
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    kind of confusing

  63. wintersuntime
    • one year ago
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    |dw:1441162041205:dw|

  64. anonymous
    • one year ago
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    there were no parentheses in the one on the left

  65. anonymous
    • one year ago
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    \[3x-1=2(x+3)\\ 2x-1=2x+6\\ x-1=6\\ x=7\]

  66. anonymous
    • one year ago
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    i made a typo there

  67. anonymous
    • one year ago
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    \[3x-1=2(x+3)\\ 3x-1=2x+6\\ x-1=6\\ x=7\]

  68. wintersuntime
    • one year ago
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    oh

  69. anonymous
    • one year ago
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    wanna try \[7 x + 20 = x + 5 \]

  70. wintersuntime
    • one year ago
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    I think i get know

  71. wintersuntime
    • one year ago
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    okay

  72. anonymous
    • one year ago
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    OOH DAMN!

  73. anonymous
    • one year ago
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    i copied and pasted, but it did not work correctly lets start again

  74. wintersuntime
    • one year ago
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    oh okay

  75. anonymous
    • one year ago
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    the first one DID have parentheses \[3(x-1)=2(x+3)\]

  76. anonymous
    • one year ago
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    steps are the same, answer is different

  77. anonymous
    • one year ago
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    distribute on both sides get \[3x-3=2x+6\]

  78. anonymous
    • one year ago
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    subtract \(2x\) to get \[x-3=6\]then add 3 gives \[x=9\]

  79. wintersuntime
    • one year ago
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    oh okay I think i get it I'll try to do the next one

  80. wintersuntime
    • one year ago
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    I hope i get it right

  81. anonymous
    • one year ago
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    ok write the steps (very similar to the last one )

  82. wintersuntime
    • one year ago
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    |dw:1441162804391:dw|

  83. anonymous
    • one year ago
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    yes

  84. wintersuntime
    • one year ago
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    then x-5

  85. anonymous
    • one year ago
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    not sure what you mean you have \[7x+140=x+5\] right? you want the x on one side of the equal sing, subtract x from both sides

  86. anonymous
    • one year ago
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    *sign

  87. wintersuntime
    • one year ago
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    x= -22.5

  88. anonymous
    • one year ago
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    yup

  89. wintersuntime
    • one year ago
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    I'll try to do the next one

  90. wintersuntime
    • one year ago
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    Is it n= 3.5

  91. anonymous
    • one year ago
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    yes

  92. wintersuntime
    • one year ago
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    I don't get the next one

  93. anonymous
    • one year ago
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    don't be scared of the fraction, go ahead and distribute first

  94. wintersuntime
    • one year ago
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    For the last one I got z= 2

  95. anonymous
    • one year ago
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    got that right

  96. wintersuntime
    • one year ago
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    okay

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is replying to Can someone tell me what button the professor is hitting...

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