- wintersuntime

Can someone be nice enough to help me please ?

- chestercat

See more answers at brainly.com

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

why not?

- anonymous

gotta ask though...

- wintersuntime

I'll post the question

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- wintersuntime

https://www.mathematicsvisionproject.org/uploads/1/1/6/3/11636986/sec1_mod3_sequences_se_71713.pdf

- wintersuntime

It's page 8 3.2

- wintersuntime

It's only this question -> Set
Topic: Evaluating Equations
Evaluate the following equations when x = { 1, 2, 3, 4, 5 }. Organize your inputs and outputs
into a table of values for each equation. Let x be the input and y be the output.

- anonymous

is the the \(4^x\) one?

- wintersuntime

yes with the table

- DanJS

ha, thanks for th ebook

- wintersuntime

I have to answer those question 5. 6. 7. 8.

- anonymous

ok in the first column put \( 1, 2, 3, 4, 5\)
in the second put \(4, 4^2, 4^3, 4^4, 4^5 \) or rather what you get when you compute those numbers

- anonymous

|dw:1441160033833:dw|

- anonymous

make yours look neater

- wintersuntime

That for question 5. right so its multipliying right

- anonymous

it is raising to powers, not multiplying
or "multiplying by itself x times"

- wintersuntime

oh

- anonymous

for example \(4^3=4\times 4\times 4=64\) not \(12\)

- wintersuntime

Can you help me with the other question please

- wintersuntime

- anonymous

what is the quesiton?

- anonymous

you mean the next one \((-3)^x\)?

- wintersuntime

yes

- anonymous

they are all the same idea
replace x by 1, 2, 3, 4, 5 and see what you get

- wintersuntime

|dw:1441161271918:dw|

- anonymous

\(x=1,y=(3)^1=-3\)
\(x=2,y=(-3)^2=9\) etc

- wintersuntime

like that ?

- anonymous

yup!

- wintersuntime

yay

- anonymous

yay indeed!

- wintersuntime

for the next one is it the same

- anonymous

for the next one it is not the same

- wintersuntime

but they are all negative

- anonymous

for the next one all the answers are negative
yeah, what you said

- anonymous

the last one is the easiest

- wintersuntime

and for the next one is it the same idea

- anonymous

10,100,1000,10000,10,000

- wintersuntime

that was easy

- anonymous

now i have a question
what is that a picture of?

- wintersuntime

what picture ?

- wintersuntime

My profile pic

- anonymous

yeah that one

- wintersuntime

It's a band from of mice and men

- wintersuntime

Of Mice & Men - Second and Sebring (Official Music Video)

- anonymous

ooh

- wintersuntime

https://www.youtube.com/watch?v=qSeiG6qMhaI

- wintersuntime

you should listen to them they are really good

- wintersuntime

hey I'm sorry to bother you but can you help me on 6 question if you can ?

- anonymous

ok

- anonymous

sure

- anonymous

if i can

- wintersuntime

okay

- wintersuntime

https://www.mathematicsvisionproject.org/uploads/1/1/6/3/11636986/sec1_mod3_sequences_se_71713.pdf

- wintersuntime

It's on page 9

- anonymous

on page 9 i see a bunch of equations, but no number 6

- wintersuntime

yes its the equations

- anonymous

\[3 x âˆ’ 1 = 2(x + 3)
\]

- anonymous

like that one?

- wintersuntime

yes

- anonymous

distribute first

- anonymous

\[3x-1=2x+6\]

- anonymous

subtract \(2x\) from both sides
\[x-1=6\]

- anonymous

then add 1 \[x=7\]

- anonymous

you got that?

- wintersuntime

kind of confusing

- wintersuntime

|dw:1441162041205:dw|

- anonymous

there were no parentheses in the one on the left

- anonymous

\[3x-1=2(x+3)\\
2x-1=2x+6\\
x-1=6\\
x=7\]

- anonymous

i made a typo there

- anonymous

\[3x-1=2(x+3)\\
3x-1=2x+6\\
x-1=6\\
x=7\]

- wintersuntime

oh

- anonymous

wanna try \[7 x + 20 = x + 5
\]

- wintersuntime

I think i get know

- wintersuntime

okay

- anonymous

OOH DAMN!

- anonymous

i copied and pasted, but it did not work correctly
lets start again

- wintersuntime

oh okay

- anonymous

the first one DID have parentheses
\[3(x-1)=2(x+3)\]

- anonymous

steps are the same, answer is different

- anonymous

distribute on both sides get \[3x-3=2x+6\]

- anonymous

subtract \(2x\) to get
\[x-3=6\]then add 3 gives \[x=9\]

- wintersuntime

oh okay I think i get it I'll try to do the next one

- wintersuntime

I hope i get it right

- anonymous

ok write the steps (very similar to the last one )

- wintersuntime

|dw:1441162804391:dw|

- anonymous

yes

- wintersuntime

then x-5

- anonymous

not sure what you mean
you have \[7x+140=x+5\] right? you want the x on one side of the equal sing, subtract x from both sides

- anonymous

*sign

- wintersuntime

x= -22.5

- anonymous

yup

- wintersuntime

I'll try to do the next one

- wintersuntime

Is it n= 3.5

- anonymous

yes

- wintersuntime

I don't get the next one

- anonymous

don't be scared of the fraction, go ahead and distribute first

- wintersuntime

For the last one I got z= 2

- anonymous

got that right

- wintersuntime

okay

Looking for something else?

Not the answer you are looking for? Search for more explanations.