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anonymous
 one year ago
Use the mass values of each element to determine the empirical formula of the tin oxide compound.
mass of tin: 2.12g
mass of oxygen: 4.5g
anonymous
 one year ago
Use the mass values of each element to determine the empirical formula of the tin oxide compound. mass of tin: 2.12g mass of oxygen: 4.5g

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DanJS
 one year ago
Best ResponseYou've already chosen the best response.3sorry, i would have to look it up, been a few years since chem, it is the reduiced formula...need to find the mass ratios i think

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3is there more than one oxide of tin mayhbe too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont think so, otherwise there would be the roman numerals right

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3yes, here are a couple examples, seems straight forward

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3https://www.chem.tamu.edu/class/majors/tutorialnotefiles/empirical.htm

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3what is the formula for the tin oxide? tin has more than one oxidation state

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0also it says tin (II) oxide

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3right that is what it is if SnO , since oxygen is 2 ion charge

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3it just follows example 1 in that link i put above

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3convert both gram masses to moles of each first...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure how to do that,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do i find it on the periodic table or something ?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3Look on the periodic table to find the mass of each element...molecular mass

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0118.71 u for tin and 15.9994 u ± 0.0004 u for oxygen

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3that is how many grams of that element are in 1 mole of that element

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3sounds right, i know oxygen is 16

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, what to do from here

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3so convert each to moles by.... dw:1441161268321:dw

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3notice grams X cancels out, it is on top and bottom

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3\[\frac{ 2.12g~Sn }{ 1}*\frac{ 1~mol~Sn }{ 118.71g~Sn }~~ \approx~~0.0179~mol~~Sn\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3remember the number from the table, 118.71 gives you the number of grams of tin per 1 mole... the second fraction used

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so tins molar mass is 0.0179 mol

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3no, tins molar mass is 118.71 g / mol (on table) 0.0179 mol tin is the same thing as 2.12 g tin that is given, just converted grams of tin to moles of tin

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3in the same way, convert the given grams of oxygen to moles of oxygen

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've gotta hit the sack now but we can continue this later, thanks!

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3follow example 1 in here https://www.chem.tamu.edu/class/majors/tutorialnotefiles/empirical.htm already converted to moles...only one step left

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@DanJS ok im back, the last step is the division correct?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3oh, yeah i think you just divide by the smallest element value

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and we have to do that for each element

DanJS
 one year ago
Best ResponseYou've already chosen the best response.30.0179 mol Sn and 0.2813 mol O one sec

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3yeah i think you just divide both by the smaller, and they should be near whole numbers

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3so 16 oxygen and one tin i guess

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3yeah, 4.5 grams of a gas is a bunch compared to 2.12g of tin

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, so theres 16 oxygen and 1 tin, how does this relate to the empirical formula of tin oxide

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3idk, i would look more into it, i just went through it with you and looked it up

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3Empirical Formula  A formula that gives the simplest wholenumber ratio of atoms in a compound. i'm not very confident in that answer though, it may be right, not sure

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3i would reask the question in a fresh thread and maybe someone can do it for sure

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks for your time

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3welcome, i remember a few chem things pretty good from the 2 semesters i had to take

DanJS
 one year ago
Best ResponseYou've already chosen the best response.3empirical formula, not so much, never used again
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