## anonymous one year ago Use the mass values of each element to determine the empirical formula of the tin oxide compound. tin: 2.12 g oxygen 4.5 g

1. Rushwr

What did u get @JoannaBlackwelder

2. anonymous

@iambatman can you help?

3. anonymous

4. Photon336

It's been a while but I think this is how you would approach a question like this: STEP #1 convert each to moles $2.10g Tin * \frac{ mol }{ 119.0g } = 0.18 moles$ $4.5g*\frac{ mol Oxygen }{ 16g } = 0.28$ STEP #2 find out which one has the least number of moles This is Tin 0.18 moles $Ti _{x}O _{y}$ STEP #3 Divide each by the lowest number of moles so we're going to divide each one 0.18. 0$\frac{ 0.18 }{ 0.18 } = 1 Tin$ $\frac{ 0.28 }{ 0.18 } = 1.5 round \to nearest whole number 2$ Hence Titanium di oxide. $TiO _{2}$ let me know if you have any questions

5. anonymous

wouldn't the empirical formula be something along the lines of SnO?

6. Photon336

@plohrb you are correct, i accidentally put the wrong abbreviation but the molar mass of tin is still 119 g/mol though

7. Photon336

$SnO _{2}$

8. anonymous

so SnO^2 is the empirical formula or the regular?

9. anonymous

nvm got it ! thanks!

10. Photon336

well it would be empirical because you cant go lower than that. that's the lowest possible ratio.

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