A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Please help!!
Determine the first five iterates of f(x)=1.2x(1x) for x0=0.1
anonymous
 one year ago
Please help!! Determine the first five iterates of f(x)=1.2x(1x) for x0=0.1

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(1 point) a) 0.108, 0.116, 0.123, 0.129, 0.135.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much! You go to connections? Do you have the rest of them?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No problem, and just add them so I can check

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No it's a practice. And the last two are fill in the blanks.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Given f(x)=2x^2+8 and g(x)=5x6 , find each function for questions 45.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Damn....kinda got me...@pooja195 , can u help??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't think he is gonna answer, he deleted his comment.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0damn...imma try and solve this one....i"m sorry if i don't get it tonight

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's all good. I will eventually figure it out.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.