## anonymous one year ago Algebra 2 Find the quotient. 2x-3/x/7/x^2 A. 7/x(2x-3) B. 7x/2x-3 C. 2x-3/7x D. x(2x-3)/7

1. Nnesha

$\huge\rm \frac{ \frac{ 2x-3 }{ x } }{ \frac{ 7 }{ x^2 } }$ like this ?

2. anonymous

so the answers is C @Nnesha

3. Nnesha

how did you get it ?

4. anonymous

I just saw what u typed me and i figure out that is was exacly urs :) @Nnesha so I'm right?

5. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @Nnesha $\huge\rm \frac{ \frac{ 2x-3 }{ x } }{ \frac{ 7 }{ x^2 } }$ like this ? $$\color{blue}{\text{End of Quote}}$$ i just asked a question is this ur question ?

6. anonymous

yes is like that the question I'm asking @Nnesha

7. Nnesha

okay change division to multiplication multiply the top with the reciprocal of the bottom fraction

8. anonymous

so i see that the answer is C @Nnesha right?

9. Nnesha

please show ur work so i can check !

10. anonymous

I did this 2x-3/7x cuz I cancel out the x^2

11. anonymous

I really dont know how to slove it :( @Nnesha

12. Nnesha

here is an example $\huge\rm \frac{ \color{Red}{\frac{ a }{ b }}}{ \frac{ c }{ d} }= \color{ReD}{\frac{a}{b}} \times \frac{d}{c}$

13. Nnesha

what is the reciprocal of the bottom fraction ??

14. anonymous

x and 7

15. Nnesha

what's reciprocal of 7/x^2 ??

16. Nnesha

reciprocal of 3/2 is 2/3

17. anonymous

7/x^2

18. Nnesha

that's the original fraction what's reciprocal of that ?

19. anonymous

i mean x^2/7 @Nnesha

20. Nnesha

yes right!

21. Nnesha

so multiply $\huge\rm \frac{ 2x-3 }{ x } \times \frac{ x^2 }{ 7}$ now multiply the numerator by numerator and denominator by denominator

22. anonymous

I got C

23. Nnesha

gtg sorry no it's not c

24. anonymous

So D?