A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

For what kind of motion are the instantaneous and average velocities equal? Why is the answer constant-velocity motion?

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @dan815 @UnkleRhaukus can you please help me?

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @DanJS

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    because there is no acceleration when an object is moving with constant velocity so the instantaneous velocity is constant. If velocity isn't changing, the average over any interval is equal to the velocity at any specific time.

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then is it possible for an object's acceleration to be zero if the velocity if zero

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Zale101

  6. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    You can't confidently say that if acceleration is zero then velocity will surely be zero or if velocity is zero then acceleration will surely be zero. Like suppose a car is moving with a constant velocity then it's in uniform motion i.e. it has a velocity but no acceleration also think what happens when we throw a ball vertically above the ground, at a instant after attaining certain height its velocity becomes zero but it is still experiencing an acceleration (acceleration due to gravity) towards the ground so a body can have a zero velocity but still be accelerated.

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok. how can you determine the speed of an object with the acceleration

  8. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \(\color{blue}{\text{Originally Posted by}}\) @prguan For what kind of motion are the instantaneous and average velocities equal? Why is the answer constant-velocity motion? \(\color{blue}{\text{End of Quote}}\) Suppose a car is moving with an accelerated motion such that its acceleration is \(\sf 1 m/s^2\). Now let's note its velocity at different instants. Time Velocity 0 0 1 1 2 2 3 3 We see that its instant velocity at different instants of time will be different like, 1, 2 and \(\sf 3 m/s\) but its average velocity will be 3m/s \(\sf (\frac{1+2+3}{3})\)

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why is the average velocity 3m/s (1+2+3)=6 6/3 is 2

  10. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    No I am sorry, average velocity will be equal to \(\sf \frac{Total~Distance}{Total~Time}\) And in the above case total distance = \(\sf (1 \times 1) +(1\times 2)+(1\times 3)\) Total time = 3 seconds, so average velocity = 2m/s

  11. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Now, let's consider the case of a car going through a constant velocity of say 3 m/s i.e. it has no acceleration. Right? Let's do the same experiment and note its velocities at various instants of time. Time Velocity 0 0 1 3 2 3 3 3 So we see that velocity this car is same at all the instant of times and not only that its average velocity is also same as its instantaneous velocity. Check this by finding out its average velocity as i did in the above table.

  12. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ok i though to find acceleration it was distance/ time

  13. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    No, Distance/Time = Velocity and this formula is only applicable when the object is moving with constant velocity i.e. it has zero acceleration. To find acceleration you can use formula, V=U+at, where, V= final velocity U= initial velocity a= acceleration t=time

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so final velocity= initial velocity + acceleration x time x where is where- displacement

  15. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what does where represent?

  16. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    No where is nothing c:

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    im confused

  18. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    No, Distance/Time = Velocity and this formula is only applicable when the object is moving with constant velocity i.e. it has zero acceleration. To find acceleration you can use formula, \(\boxed{V=U+at}\) Where, the symbols has following meaning V= final velocity U= initial velocity a= acceleration t=time

  19. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Is it clear now?

  20. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i guess

  21. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.