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anonymous
 one year ago
For what kind of motion are the instantaneous and average velocities equal?
Why is the answer constantvelocity motion?
anonymous
 one year ago
For what kind of motion are the instantaneous and average velocities equal? Why is the answer constantvelocity motion?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 @UnkleRhaukus can you please help me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because there is no acceleration when an object is moving with constant velocity so the instantaneous velocity is constant. If velocity isn't changing, the average over any interval is equal to the velocity at any specific time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then is it possible for an object's acceleration to be zero if the velocity if zero

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.2You can't confidently say that if acceleration is zero then velocity will surely be zero or if velocity is zero then acceleration will surely be zero. Like suppose a car is moving with a constant velocity then it's in uniform motion i.e. it has a velocity but no acceleration also think what happens when we throw a ball vertically above the ground, at a instant after attaining certain height its velocity becomes zero but it is still experiencing an acceleration (acceleration due to gravity) towards the ground so a body can have a zero velocity but still be accelerated.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. how can you determine the speed of an object with the acceleration

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @prguan For what kind of motion are the instantaneous and average velocities equal? Why is the answer constantvelocity motion? \(\color{blue}{\text{End of Quote}}\) Suppose a car is moving with an accelerated motion such that its acceleration is \(\sf 1 m/s^2\). Now let's note its velocity at different instants. Time Velocity 0 0 1 1 2 2 3 3 We see that its instant velocity at different instants of time will be different like, 1, 2 and \(\sf 3 m/s\) but its average velocity will be 3m/s \(\sf (\frac{1+2+3}{3})\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why is the average velocity 3m/s (1+2+3)=6 6/3 is 2

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.2No I am sorry, average velocity will be equal to \(\sf \frac{Total~Distance}{Total~Time}\) And in the above case total distance = \(\sf (1 \times 1) +(1\times 2)+(1\times 3)\) Total time = 3 seconds, so average velocity = 2m/s

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.2Now, let's consider the case of a car going through a constant velocity of say 3 m/s i.e. it has no acceleration. Right? Let's do the same experiment and note its velocities at various instants of time. Time Velocity 0 0 1 3 2 3 3 3 So we see that velocity this car is same at all the instant of times and not only that its average velocity is also same as its instantaneous velocity. Check this by finding out its average velocity as i did in the above table.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok i though to find acceleration it was distance/ time

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.2No, Distance/Time = Velocity and this formula is only applicable when the object is moving with constant velocity i.e. it has zero acceleration. To find acceleration you can use formula, V=U+at, where, V= final velocity U= initial velocity a= acceleration t=time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so final velocity= initial velocity + acceleration x time x where is where displacement

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what does where represent?

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.2No where is nothing c:

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.2No, Distance/Time = Velocity and this formula is only applicable when the object is moving with constant velocity i.e. it has zero acceleration. To find acceleration you can use formula, \(\boxed{V=U+at}\) Where, the symbols has following meaning V= final velocity U= initial velocity a= acceleration t=time
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