dumbsearch2
  • dumbsearch2
TRIGONOMETRY: Start with sin2(θ) + cos2(θ) = 1. What would you multiply through by to get sec2(θ) = tan2(θ) + 1?
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

dumbsearch2
  • dumbsearch2
Nnesha
  • Nnesha
what is reciprocal of tan ?
DanJS
  • DanJS
sorry, i was still on the closed first question of this

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

dumbsearch2
  • dumbsearch2
cotangent @nnesha
dumbsearch2
  • dumbsearch2
So is the answer D?
DanJS
  • DanJS
try each answer out to see if it will work...
Nnesha
  • Nnesha
not just cot it should be 1/cot but how would you write tan in terms of sin cos ?
DanJS
  • DanJS
you just need to know the basic definitions of the trig functions, and multiply through each anser to test if it works
DanJS
  • DanJS
For example in using A) 1/cos^2(x) multiplying the given equation by that results in \[\frac{ \sin^2(x) }{ \cos^2(x) }+\frac{ \cos^2(x) }{ \cos^2(x) } = \frac{ 1 }{ \cos^2(x) }\]
DanJS
  • DanJS
see if that is the same as the equation they are looking for
dumbsearch2
  • dumbsearch2
I get tan^2(x), not sec.
DanJS
  • DanJS
right, sin^2 / cos^2 = tan^2 for the first fraction
DanJS
  • DanJS
do that for all 3
DanJS
  • DanJS
cos^2 / cos^2 = 1
DanJS
  • DanJS
and 1 / cos^2(x) = sec(x)^2 right
dumbsearch2
  • dumbsearch2
So the answer is A?
DanJS
  • DanJS
it appears so, because you get tan^2(x) + 1 = sec^2(x)
DanJS
  • DanJS
memorize the 6 trig vunctions and how they relate... tha tis all this is

Looking for something else?

Not the answer you are looking for? Search for more explanations.