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dumbsearch2

  • one year ago

TRIGONOMETRY: Start with sin2(θ) + cos2(θ) = 1. What would you multiply through by to get sec2(θ) = tan2(θ) + 1?

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  1. dumbsearch2
    • one year ago
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  2. Nnesha
    • one year ago
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    what is reciprocal of tan ?

  3. DanJS
    • one year ago
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    sorry, i was still on the closed first question of this

  4. dumbsearch2
    • one year ago
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    cotangent @nnesha

  5. dumbsearch2
    • one year ago
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    So is the answer D?

  6. DanJS
    • one year ago
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    try each answer out to see if it will work...

  7. Nnesha
    • one year ago
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    not just cot it should be 1/cot but how would you write tan in terms of sin cos ?

  8. DanJS
    • one year ago
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    you just need to know the basic definitions of the trig functions, and multiply through each anser to test if it works

  9. DanJS
    • one year ago
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    For example in using A) 1/cos^2(x) multiplying the given equation by that results in \[\frac{ \sin^2(x) }{ \cos^2(x) }+\frac{ \cos^2(x) }{ \cos^2(x) } = \frac{ 1 }{ \cos^2(x) }\]

  10. DanJS
    • one year ago
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    see if that is the same as the equation they are looking for

  11. dumbsearch2
    • one year ago
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    I get tan^2(x), not sec.

  12. DanJS
    • one year ago
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    right, sin^2 / cos^2 = tan^2 for the first fraction

  13. DanJS
    • one year ago
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    do that for all 3

  14. DanJS
    • one year ago
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    cos^2 / cos^2 = 1

  15. DanJS
    • one year ago
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    and 1 / cos^2(x) = sec(x)^2 right

  16. dumbsearch2
    • one year ago
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    So the answer is A?

  17. DanJS
    • one year ago
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    it appears so, because you get tan^2(x) + 1 = sec^2(x)

  18. DanJS
    • one year ago
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    memorize the 6 trig vunctions and how they relate... tha tis all this is

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