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anonymous
 one year ago
TRIGONOMETRY:
Start with sin2(θ) + cos2(θ) = 1. What would you multiply through by to get sec2(θ) = tan2(θ) + 1?
anonymous
 one year ago
TRIGONOMETRY: Start with sin2(θ) + cos2(θ) = 1. What would you multiply through by to get sec2(θ) = tan2(θ) + 1?

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0what is reciprocal of tan ?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1sorry, i was still on the closed first question of this

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1try each answer out to see if it will work...

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0not just cot it should be 1/cot but how would you write tan in terms of sin cos ?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1you just need to know the basic definitions of the trig functions, and multiply through each anser to test if it works

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1For example in using A) 1/cos^2(x) multiplying the given equation by that results in \[\frac{ \sin^2(x) }{ \cos^2(x) }+\frac{ \cos^2(x) }{ \cos^2(x) } = \frac{ 1 }{ \cos^2(x) }\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1see if that is the same as the equation they are looking for

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I get tan^2(x), not sec.

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1right, sin^2 / cos^2 = tan^2 for the first fraction

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1and 1 / cos^2(x) = sec(x)^2 right

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1it appears so, because you get tan^2(x) + 1 = sec^2(x)

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1memorize the 6 trig vunctions and how they relate... tha tis all this is
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