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anonymous
 one year ago
Long division for x^4  2x^3 + 3x^2  4x + 6 by x^2 + 2x 1?
anonymous
 one year ago
Long division for x^4  2x^3 + 3x^2  4x + 6 by x^2 + 2x 1?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x ^{2} + 2x  1 \div x ^{4}  2x ^{3} + 3x ^{2}  4x + 6\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x ^{4}  2x^3 + 3x^2  4x + 6 \div x^2 + 2x  1\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0\[\ \large \frac{ x^4  2x^3 + 3x^2  4x + 6 }{ x^2 +2x  1 }\] when u r dividing, you are basically subtracting the exponents with the same root for example \[\large \frac{ x^6 }{ x^2 } = x^4\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0and if we have \[\large 2x \] then the exponent is 1 \[\large 2x^1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would x^4 end up divided (subtracting, I guess) by x^2, turning into x^2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441163299335:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441164156039:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You also need a place holder for the x² termdw:1441164237673:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441164097336:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have no idea where or why I put 1/4x.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441164511713:dw Do you follow this?dw:1441164769424:dw