## anonymous one year ago A piece of aluminum has a volume of 3.94 x 10-3 m3. The coefficient of volume expansion for aluminum is = 69 x 10-6(C°)-1. The temperature of this object is raised from 1.20 to 311 oC. How much work is done by the expanding aluminum if the air pressure is 1.01 x 105 Pa?

1. Michele_Laino

hint: first, we have to compute the final volume, which is given by the subsequent formula: $\Large {V_1} = {V_0}\left( {1 + 3\lambda \Delta t} \right)$ where: $\Large \begin{gathered} \lambda = 69 \cdot {10^{ - 6}}\;{\left( {^\circ C} \right)^{ - 1}},\quad \Delta t = 311 - 1.2 = ...^\circ C \hfill \\ \quad \hfill \\ {V_0} = 3.94 \cdot {10^{ - 3}}{m^3} \hfill \\ \end{gathered}$ second step: the requested work L, done by the system, namely done by our cube of aluminum, is: $\Large L = {P_0}\left( {{V_1} - {V_0}} \right)$

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