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anonymous
 one year ago
I need help with simplifying
anonymous
 one year ago
I need help with simplifying

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[6a \sqrt{80b}\sqrt{180a ^{2}b}+5a \sqrt{b}\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Look at the middle term and take the prime factorization of 180

anonymous
 one year ago
Best ResponseYou've already chosen the best response.060 & 2 for 180 then 40&2 for 80 right?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0\[6a\sqrt{20\cdot 2 \cdot 2 \cdot b} \sqrt{20 \cdot 9 \cdot a\cdot a \cdot b}+5a\sqrt{b}\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0\[60 \cdot 2 \ne 180\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Yes that works too :)

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0now factor both 20's and the 9 into simpler, prime factors.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.010 x 2 for 20's & 3 x 3 for 9

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Good. \[6a\sqrt{10\cdot 2\cdot 2 \cdot 2 \cdot b} \sqrt{10 \cdot 2 \cdot 3\cdot 3 \cdot a\cdot a \cdot b}+5a\sqrt{b}\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0factor both 10's one more time into prime factors.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Great \(\checkmark\) \[6a\sqrt{5\cdot 2\cdot 2\cdot 2 \cdot 2 \cdot b} \sqrt{5\cdot 2 \cdot 2 \cdot 3\cdot 3 \cdot a\cdot a \cdot b}+5a\sqrt{b}\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Now for every fair of 2 numbers, 1 of them will be extracted from the square root and multiplied to the term outside the square root.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0For example, to start you off. \[6a\sqrt{5\color{blue}{\cdot 2\cdot 2}\color{red}{\cdot 2 \cdot 2} \cdot b} = 6a \cdot \color{blue}{2} \cdot \color{red}{2}\sqrt{5 \cdot b}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[48a \sqrt{5\times2timesb}6a \sqrt{5\times2\times3 \times a \times b}+5a \sqrt{b}\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Not quite. In the first part you still have a 2 left within the square root when its been paired off and pulled out already. You should just have a 5 and a b left within the square root there since they are lone pairs and cannot be pulled out. Once things are paired off, they are not rewritten within the square root. Second part, the 6a looks right, therefore the only thing that should be left within the square root should be 5 and b.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh okay i think i got it now

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0It should look like this: \[6a\sqrt{5\color{blue}{\cdot 2\cdot 2}\color{red}{\cdot 2 \cdot 2} \cdot b} = 6a \cdot \color{blue}{2} \cdot \color{red}{2}\sqrt{5 \cdot b} = 24a\sqrt{5b}\]\[ \sqrt{5\cdot\color{red}{ 2 \cdot 2} \cdot \color{blue}{3\cdot 3} \cdot \color{green}{a\cdot a} \cdot b} = 6a\sqrt{5b}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah thats what i got

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441173348642:dw

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0\[(24a6a)\sqrt{5b} +5a\sqrt{b}= 18a\sqrt{5b}+5a\sqrt{b} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yup, and thank you for your help
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