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|dw:1441174469829:dw|

will we consider gravity ?

|dw:1441175324916:dw|

yeah we need to consider that mid line only i think too, since this is case where the speed is equal

|dw:1441175465518:dw|

yeah that angle should be same

now with in this angle space itself we should find the prob and then see what the total prob is

**how much angle difference**

sometimes i m surprised at my own english hehe

|dw:1441175544779:dw|

it doesnt have to be a perfect collision though, it can be off course as long as they touch

cant we treat the bubbles as point masses

oh they gave radius ok

|dw:1441175998926:dw|

ummm....i am little confused but is this the answer-
probability=L/[2(W+L)]

there is some modular form of solution for this problem if u limit the angles these circles can travel to 2pi*k/n , where 0

tbh i dont know yet qwerty id have to see your full work

here is one way of approaching it

|dw:1441176643347:dw|

as the perfect collision surface area thins out with the angle from the center

|dw:1441176750326:dw|

ya it is definately something simliar to that

the only main thing to consider is how the difference in angle changes

as u move above the straight line

for imperfect collisions

|dw:1441176897902:dw|

yah that might actually still be equal if we just use point masses in the end