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anonymous
 one year ago
when a source is connected to a 2 ohm resistor the current is 0.5 ampere if the same source is connected to a 5 ohm resistor the current is 0.25 find the potential of the battery??
anonymous
 one year ago
when a source is connected to a 2 ohm resistor the current is 0.5 ampere if the same source is connected to a 5 ohm resistor the current is 0.25 find the potential of the battery??

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@arindameducationusc

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0\[V = IR = 2 * 0.5 \ne 5 *0.25\] post/link original question?!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.6I think that in your circuit we have to consider the internal resistance R0 of the battery, so we have the subsequent equation: \[\Large E = \left( {R + {R_0}} \right)I\] where E is the electromotive force of your battery, and R is the external resistance. Using your data, we get the subsequent algebraic system of two equations: \[\Large \left\{ \begin{gathered} E = \left( {2 + {R_0}} \right) \cdot 0.5 \hfill \\ E = \left( {5 + {R_0}} \right) \cdot 0.25 \hfill \\ \end{gathered} \right.\] Please solve it for E

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino cool!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.6thanks! :) @IrishBoy123

radar
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino A correct and wise assumption. Most problems ignore internal resistance considering an ideal source. This case, it matters.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nice @Michele_Laino :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino how can we get R0 because its not given???

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.6thanks! :) @iambatman @radar

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.6If we equate, each other, both right sides of the two equations above, we get: \[\Large \left( {2 + {R_0}} \right) \cdot 0.5 = \left( {5 + {R_0}} \right) \cdot 0.25\] which is an equation of first degree in R0. Please solve it for R0. @ShirazKhokhar
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