surryyy
  • surryyy
Select the equation of the line graphed below: y + 7 = 1(x + 6) y – 7 = 1(x – 6) y + 6 = 1(x + 7) y – 6 = 1(x – 7) https://static.k12.com/eli/bb/1211/4_68960/2_33580_12_68972/e1120da006e352e437dc8fe29146b21aef604445/media/79f8ace6ffc61f82a31f6c5ce5ecbce34a8a0321/mediaasset_958465_1.jpg
Mathematics
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surryyy
  • surryyy
Select the equation of the line graphed below: y + 7 = 1(x + 6) y – 7 = 1(x – 6) y + 6 = 1(x + 7) y – 6 = 1(x – 7) https://static.k12.com/eli/bb/1211/4_68960/2_33580_12_68972/e1120da006e352e437dc8fe29146b21aef604445/media/79f8ace6ffc61f82a31f6c5ce5ecbce34a8a0321/mediaasset_958465_1.jpg
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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imqwerty
  • imqwerty
select any 2 points that lie on the line for example -http://prntscr.com/8bp02w and then apply 2 point form which is - \[\frac{ y-y _{1} }{ y_{2}-y_{1} }=\frac{ x-x_{1} }{ x_{2}-x_{1} }\] where (x1,y2) and (x2,y2) are the cordinates of the 2 points :)
Michele_Laino
  • Michele_Laino
your line passes at point (7,6). For example if I substitute x=7 and y=6, into the secondequation, I get: \[\Large \begin{gathered} 6 - 7 = 1 \cdot \left( {7 - 6} \right) \hfill \\ \hfill \\ - 1 = 1 \hfill \\ \end{gathered} \] which is a false statement, so the second option can not be the right option. Please do the same with the other options
imqwerty
  • imqwerty
or u can do as @Michele_Laino said :) select any point the lies on the line an put its x and y cordinates in the options nd the one which satisfies is the answer :)

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imqwerty
  • imqwerty
but sometimes it may happen that more than 1 equation satisfy the reason is that, that point may be the solution to those lines :) |dw:1441188655630:dw|
surryyy
  • surryyy
would it be c?
Michele_Laino
  • Michele_Laino
I think no, since if I substitute x=7 and y=6 into the third equation, I get: \[\Large \begin{gathered} 6 + 6 = 1 \cdot \left( {7 + 7} \right) \hfill \\ \hfill \\ 12 = 14 \hfill \\ \end{gathered} \] which, again, is a flase statement
Michele_Laino
  • Michele_Laino
false*
surryyy
  • surryyy
so a
Michele_Laino
  • Michele_Laino
that's right!
surryyy
  • surryyy
thnx
Michele_Laino
  • Michele_Laino
:)

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