3-2{7x-[-2(3x-1)+3(5x-3^2)]}
I feel like i got it buttttt get confused plzz hpl

- anonymous

3-2{7x-[-2(3x-1)+3(5x-3^2)]}
I feel like i got it buttttt get confused plzz hpl

- jamiebookeater

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- Vocaloid

start from the innermost parentheses/brackets and work your way outside
let's start with -2(3x-1) = ?

- anonymous

+6x + 2?

- Vocaloid

almost, check the sign on 6x

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## More answers

- anonymous

i get confused with the negatives and positives..

- anonymous

oh -6x

- Vocaloid

right

- anonymous

Can i show you how i wrote it?

- Vocaloid

negative*positive = negative

- Vocaloid

sure

- anonymous

3-2 {7x-[-6x+2) + (15x-27)]
3+ - 14x + 12x -4 + -30x +54
i think im doing something wrong.. i dont know

- freckles

you did all of that in one step?
if so I think you are doing too many steps in one step

- anonymous

what ?

- freckles

I'm just saying because you did so many steps in one step you have made a couple of mistakes

- anonymous

maybe..

- freckles

no i'm sure

- freckles

I think @Vocaloid was going to take you through the process

- anonymous

Yeah idk

- freckles

if i were you I would use the distributive property for the inner parts then move on to the outer parts

- dinamix

@glitterythings [-2(3x-1)+3(5x-3^2)] find this first and after {7x-[-2(3x-1)+3(5x-3^2)]}

- anonymous

I did that i thought , i might of skipped a step hold on

- anonymous

Ill just figure it out myself thank you guys!

- freckles

\[3-2{7x-[-2(3x-1)+3(5x-3^2)]} \\ \text{ like first things I would do } \\ -2(3x-1) \text{ and } 3(5x-3^2)\]

- anonymous

I did that.. but i didnt put it in

- freckles

that problem did not copy over to latex well

- dinamix

[-2(3x-1)+3(5x-3^2)] = 9x-26

- anonymous

oh i get what you guys are trying to tell me

- freckles

\[3-2\{7x-[-2(3x-1)+3(5x-3^2)]\}\]
there we go

- anonymous

then it would be
3- 2{7x - [-2(3x-1) + 3(5x - 9)] right?

- freckles

isn't that thing in the [ ] 9x-25?

- freckles

- dinamix

yup it is

- dinamix

i make mistake

- dinamix

{7x-[-2(3x-1)+3(5x-3^2)]} =7x-9x+25 =-2x+25

- freckles

\[3-2\{7x-[-2(3x-1)+3(5x-3^2)]\} \\ 3-2\{7x-[-6x+2+15x-27]\} \\ 3-2\{7x-[9x-25]\} \\ \]

- freckles

anyways @glitterythings maybe you can try from here?

- anonymous

yeah i can !

- dinamix

@freckles u find it 4x-(4!+4!-1)

- anonymous

@dinamix im working on it rn :)

- anonymous

i got 4x - 47

- dinamix

yup @glitterythings this the answer ;D

- anonymous

Ty :D

- anonymous

i have another question it has to do the same thing , and i think i did it wrong lol.

- dinamix

ok ask @glitterythings

- anonymous

4y^2 - 3 {2y^2 -[(4y^2-y+2) - (3y^2 +2y-5)]}

- dinamix

Start with this [(4y^2-y+2) - (3y^2 +2y-5)] u should try with me okey @glitterythings

- anonymous

i am i solved, but answer is wrong.
The answer is supposed to be y^2 - 9y +21

- anonymous

ill re write again :)

- anonymous

does everything become negative except for 5?

- dinamix

u find it y^2-9y+21 ?

- anonymous

not yet

- dinamix

cuz i find like that

- anonymous

you did? ugh idk what im doing wrong

- dinamix

yup ,ok first i show my method start [(4y^2-y+2) - (3y^2 +2y-5)] this and tell me what u find okey

- dinamix

i want see where is your mistake

- anonymous

4y2 - 3y2 = 1
-y+2y = 1
2 + -5 = -3?

- anonymous

i might be doing my math wrong

- dinamix

yup i find your mistake u forget Distribution - on this equeation - (3y^2 +2y-5)

- anonymous

oh lol

- anonymous

it would be -3y2 -2y +5?

- dinamix

yup

- dinamix

u have to focus @glitterythings (sorry if i was rude)

- anonymous

so then [ y2 -3y + 7?]

- anonymous

you arent.

- dinamix

yup this

- dinamix

{2y^2 -[(4y^2-y+2) - (3y^2 +2y-5)]} now second try for this

- dinamix

- anonymous

oh i thought i did lol

- dinamix

so u find it @glitterythings

- anonymous

i think so.

- anonymous

y2 + 3y -7?

- dinamix

yup

- anonymous

OMG I FOUND ITT!

- anonymous

YAY THANKS SO MUCH!

- dinamix

we didnt do it really u have to complete it -_-

- anonymous

oh well i figured it out lol but okay lets complete it

- dinamix

give me your steps okey

- anonymous

so then you multiply by -3
4y2 -3 (y2+3y - 7)
4y2-3y2 - 9y +21
= y2 -9y+21

- anonymous

thank you for being patient w me.

- dinamix

yup this @glitterythings no problem u are welcome but i hope u understand the steps

- anonymous

yeah i do, its like PEMDAS
and you have to solve everything in brackets,

- dinamix

ok that s make feel happy to help u ^^

- anonymous

:)

- dinamix

@glitterythings any other question ?

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