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anonymous

  • one year ago

3-2{7x-[-2(3x-1)+3(5x-3^2)]} I feel like i got it buttttt get confused plzz hpl

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  1. Vocaloid
    • one year ago
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    start from the innermost parentheses/brackets and work your way outside let's start with -2(3x-1) = ?

  2. anonymous
    • one year ago
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    +6x + 2?

  3. Vocaloid
    • one year ago
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    almost, check the sign on 6x

  4. anonymous
    • one year ago
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    i get confused with the negatives and positives..

  5. anonymous
    • one year ago
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    oh -6x

  6. Vocaloid
    • one year ago
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    right

  7. anonymous
    • one year ago
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    Can i show you how i wrote it?

  8. Vocaloid
    • one year ago
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    negative*positive = negative

  9. Vocaloid
    • one year ago
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    sure

  10. anonymous
    • one year ago
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    3-2 {7x-[-6x+2) + (15x-27)] 3+ - 14x + 12x -4 + -30x +54 i think im doing something wrong.. i dont know

  11. freckles
    • one year ago
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    you did all of that in one step? if so I think you are doing too many steps in one step

  12. anonymous
    • one year ago
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    what ?

  13. freckles
    • one year ago
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    I'm just saying because you did so many steps in one step you have made a couple of mistakes

  14. anonymous
    • one year ago
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    maybe..

  15. freckles
    • one year ago
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    no i'm sure

  16. freckles
    • one year ago
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    I think @Vocaloid was going to take you through the process

  17. anonymous
    • one year ago
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    Yeah idk

  18. freckles
    • one year ago
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    if i were you I would use the distributive property for the inner parts then move on to the outer parts

  19. dinamix
    • one year ago
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    @glitterythings [-2(3x-1)+3(5x-3^2)] find this first and after {7x-[-2(3x-1)+3(5x-3^2)]}

  20. anonymous
    • one year ago
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    I did that i thought , i might of skipped a step hold on

  21. anonymous
    • one year ago
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    Ill just figure it out myself thank you guys!

  22. freckles
    • one year ago
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    \[3-2{7x-[-2(3x-1)+3(5x-3^2)]} \\ \text{ like first things I would do } \\ -2(3x-1) \text{ and } 3(5x-3^2)\]

  23. anonymous
    • one year ago
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    I did that.. but i didnt put it in

  24. freckles
    • one year ago
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    that problem did not copy over to latex well

  25. dinamix
    • one year ago
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    [-2(3x-1)+3(5x-3^2)] = 9x-26

  26. anonymous
    • one year ago
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    oh i get what you guys are trying to tell me

  27. freckles
    • one year ago
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    \[3-2\{7x-[-2(3x-1)+3(5x-3^2)]\}\] there we go

  28. anonymous
    • one year ago
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    then it would be 3- 2{7x - [-2(3x-1) + 3(5x - 9)] right?

  29. freckles
    • one year ago
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    isn't that thing in the [ ] 9x-25?

  30. freckles
    • one year ago
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    @dinamix

  31. dinamix
    • one year ago
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    yup it is

  32. dinamix
    • one year ago
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    i make mistake

  33. dinamix
    • one year ago
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    {7x-[-2(3x-1)+3(5x-3^2)]} =7x-9x+25 =-2x+25

  34. freckles
    • one year ago
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    \[3-2\{7x-[-2(3x-1)+3(5x-3^2)]\} \\ 3-2\{7x-[-6x+2+15x-27]\} \\ 3-2\{7x-[9x-25]\} \\ \]

  35. freckles
    • one year ago
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    anyways @glitterythings maybe you can try from here?

  36. anonymous
    • one year ago
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    yeah i can !

  37. dinamix
    • one year ago
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    @freckles u find it 4x-(4!+4!-1)

  38. anonymous
    • one year ago
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    @dinamix im working on it rn :)

  39. anonymous
    • one year ago
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    i got 4x - 47

  40. dinamix
    • one year ago
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    yup @glitterythings this the answer ;D

  41. anonymous
    • one year ago
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    Ty :D

  42. anonymous
    • one year ago
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    i have another question it has to do the same thing , and i think i did it wrong lol.

  43. dinamix
    • one year ago
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    ok ask @glitterythings

  44. anonymous
    • one year ago
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    4y^2 - 3 {2y^2 -[(4y^2-y+2) - (3y^2 +2y-5)]}

  45. dinamix
    • one year ago
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    Start with this [(4y^2-y+2) - (3y^2 +2y-5)] u should try with me okey @glitterythings

  46. anonymous
    • one year ago
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    i am i solved, but answer is wrong. The answer is supposed to be y^2 - 9y +21

  47. anonymous
    • one year ago
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    ill re write again :)

  48. anonymous
    • one year ago
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    does everything become negative except for 5?

  49. dinamix
    • one year ago
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    u find it y^2-9y+21 ?

  50. anonymous
    • one year ago
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    not yet

  51. dinamix
    • one year ago
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    cuz i find like that

  52. anonymous
    • one year ago
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    you did? ugh idk what im doing wrong

  53. dinamix
    • one year ago
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    yup ,ok first i show my method start [(4y^2-y+2) - (3y^2 +2y-5)] this and tell me what u find okey

  54. dinamix
    • one year ago
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    i want see where is your mistake

  55. anonymous
    • one year ago
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    4y2 - 3y2 = 1 -y+2y = 1 2 + -5 = -3?

  56. anonymous
    • one year ago
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    i might be doing my math wrong

  57. dinamix
    • one year ago
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    yup i find your mistake u forget Distribution - on this equeation - (3y^2 +2y-5)

  58. anonymous
    • one year ago
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    oh lol

  59. anonymous
    • one year ago
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    it would be -3y2 -2y +5?

  60. dinamix
    • one year ago
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    yup

  61. dinamix
    • one year ago
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    u have to focus @glitterythings (sorry if i was rude)

  62. anonymous
    • one year ago
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    so then [ y2 -3y + 7?]

  63. anonymous
    • one year ago
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    you arent.

  64. dinamix
    • one year ago
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    yup this

  65. dinamix
    • one year ago
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    {2y^2 -[(4y^2-y+2) - (3y^2 +2y-5)]} now second try for this

  66. dinamix
    • one year ago
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    @glitterythings

  67. anonymous
    • one year ago
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    oh i thought i did lol

  68. dinamix
    • one year ago
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    so u find it @glitterythings

  69. anonymous
    • one year ago
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    i think so.

  70. anonymous
    • one year ago
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    y2 + 3y -7?

  71. dinamix
    • one year ago
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    yup

  72. anonymous
    • one year ago
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    OMG I FOUND ITT!

  73. anonymous
    • one year ago
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    YAY THANKS SO MUCH!

  74. dinamix
    • one year ago
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    we didnt do it really u have to complete it -_-

  75. anonymous
    • one year ago
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    oh well i figured it out lol but okay lets complete it

  76. dinamix
    • one year ago
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    give me your steps okey

  77. anonymous
    • one year ago
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    so then you multiply by -3 4y2 -3 (y2+3y - 7) 4y2-3y2 - 9y +21 = y2 -9y+21

  78. anonymous
    • one year ago
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    thank you for being patient w me.

  79. dinamix
    • one year ago
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    yup this @glitterythings no problem u are welcome but i hope u understand the steps

  80. anonymous
    • one year ago
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    yeah i do, its like PEMDAS and you have to solve everything in brackets,

  81. dinamix
    • one year ago
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    ok that s make feel happy to help u ^^

  82. anonymous
    • one year ago
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    :)

  83. dinamix
    • one year ago
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    @glitterythings any other question ?

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