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anonymous

  • one year ago

math help

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  1. anonymous
    • one year ago
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    g and h are both intergers ​​ −6x+5=(x+g)(x+h) there are two possible values for g. Write one of them below

  2. anonymous
    • one year ago
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    @pooja195

  3. anonymous
    • one year ago
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    @ganeshie8 @Loser66

  4. anonymous
    • one year ago
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    tbh i dont know

  5. anonymous
    • one year ago
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    @phi

  6. anonymous
    • one year ago
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    @Loser66

  7. anonymous
    • one year ago
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    @texaschic101 @Majesty69

  8. anonymous
    • one year ago
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    sorry didnt see you my b

  9. phi
    • one year ago
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    are there any other questions before this one? can you make a screen copy of this question. It is not making sense. Maybe more info will help

  10. anonymous
    • one year ago
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    ight i will try

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  11. anonymous
    • one year ago
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    try this @phi u might have to zoom in to see the question

  12. phi
    • one year ago
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    ok, it makes more sense the question should read \[ x^2−6x+5=(x+g)(x+h) \] they want you to factor x^2-6x+5 can you do that ?

  13. anonymous
    • one year ago
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    uhh hold up plz

  14. phi
    • one year ago
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    to factor you follow a complicated plan: look at the last number, and list the ways you can multiply 2 numbers to get 5 1,5 is the only choice (24 would be 1,24; 2,12; 3,8; 4,6;) the + sign on the last number +5 means the two factors are the same sign now look at the middle number -6. the - means the bigger factor is negative. because the factors have the same sign (from the first rule), that means both factors are negative. look at your list 1,5 (it is short, only 1 pair, so if there is an answer , this will be it) make both negative -1, -5 now add and if you get the middle number, you found the factors -1+ -5= -6 so those are the factors write (x-1)(x-5)

  15. anonymous
    • one year ago
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    uhh im lost@phi

  16. phi
    • one year ago
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    It is hard to explain here. if you have time, see https://www.khanacademy.org/math/algebra2/polynomial_and_rational/quad_factoring/v/factoring-quadratic-expressions

  17. anonymous
    • one year ago
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    sorry phi but im bout to get a friend in n im on khan acadmy i have my own thing

  18. anonymous
    • one year ago
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    @greenmanbay

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