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anonymous
 one year ago
math help
anonymous
 one year ago
math help

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0g and h are both intergers −6x+5=(x+g)(x+h) there are two possible values for g. Write one of them below

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@texaschic101 @Majesty69

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry didnt see you my b

phi
 one year ago
Best ResponseYou've already chosen the best response.0are there any other questions before this one? can you make a screen copy of this question. It is not making sense. Maybe more info will help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0try this @phi u might have to zoom in to see the question

phi
 one year ago
Best ResponseYou've already chosen the best response.0ok, it makes more sense the question should read \[ x^2−6x+5=(x+g)(x+h) \] they want you to factor x^26x+5 can you do that ?

phi
 one year ago
Best ResponseYou've already chosen the best response.0to factor you follow a complicated plan: look at the last number, and list the ways you can multiply 2 numbers to get 5 1,5 is the only choice (24 would be 1,24; 2,12; 3,8; 4,6;) the + sign on the last number +5 means the two factors are the same sign now look at the middle number 6. the  means the bigger factor is negative. because the factors have the same sign (from the first rule), that means both factors are negative. look at your list 1,5 (it is short, only 1 pair, so if there is an answer , this will be it) make both negative 1, 5 now add and if you get the middle number, you found the factors 1+ 5= 6 so those are the factors write (x1)(x5)

phi
 one year ago
Best ResponseYou've already chosen the best response.0It is hard to explain here. if you have time, see https://www.khanacademy.org/math/algebra2/polynomial_and_rational/quad_factoring/v/factoringquadraticexpressions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry phi but im bout to get a friend in n im on khan acadmy i have my own thing
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