A community for students.
Here's the question you clicked on:
 0 viewing
Loser66
 one year ago
What is wrong with this?
\(1 + x+x^2 +\cdots +x^n = \sum_{j =0}^n x^j\)
Hence \(1+x +x^2 +\cdots +x^{n1}\\= x^{n1}+1+x +x^2+\cdots +x^n = x^{n1}+\sum_{j=0}^n x^j = x^{n+1}+\dfrac{x^n 1}{x 1}\)
continue on comment
Please, explain me.
Loser66
 one year ago
What is wrong with this? \(1 + x+x^2 +\cdots +x^n = \sum_{j =0}^n x^j\) Hence \(1+x +x^2 +\cdots +x^{n1}\\= x^{n1}+1+x +x^2+\cdots +x^n = x^{n1}+\sum_{j=0}^n x^j = x^{n+1}+\dfrac{x^n 1}{x 1}\) continue on comment Please, explain me.

This Question is Closed

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0\(=\dfrac{(x1)(x^{n+1})+(x^n1)}{x1}\\=\dfrac{x^{n+2}x^{n+1}+x^n 1}{x1}\)

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0While when we go directly from \(1+x + x^2 +\cdots + x^{n1}= \sum_{j =0}^n x^{j 1}=\dfrac{x^n 1}{x1}\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0looks there are several typoes with  and + in the main question could you pls double check

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0\[1+x+x^2 +\cdots+x^n =\sum_{j=0}^n x^j =\dfrac{x^{n+1}1}{x1}\] \[1+x+x^2 +\cdots +x^n+x^{n1} = (\sum_{j=0}^n x^j) + x^{n1}\\=\dfrac{x^{n+1}1}{x1}+x^{n1}\] Simplify it, I get \(\dfrac{(x^{n+1}1)+(x^{n1}(x1))}{x1}\) open parentheses of the numerator: \[\dfrac{x^{n+1} 1+x^n x^{n1}}{x1}\]

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0But if I apply directly the formula \[\sum_{j=0}^n x^{j1}= \dfrac{x^n 1}{x1}\] it is different from the above. Why?

dan815
 one year ago
Best ResponseYou've already chosen the best response.2okay here is the geometric series formula

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0but that is the sum of 1 + x+ x^2 +....+x^n how about 1+x +x^2+.... +x^(n1)?

dan815
 one year ago
Best ResponseYou've already chosen the best response.21+x +x^2+.... +x^(n1) = (X^n1)/(x1)

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0hahaha.... I got you. I am dummy!! I interpret it as 1+x+x^2 +......+x^n then add one more term +x^(n1) while it should be interpret as 1 + x+x^2 +....+x^(n1) without the last term eeeeeeeeeeeh!! thank you very much, dan , the fake girl!!

dan815
 one year ago
Best ResponseYou've already chosen the best response.2yeah just remember if u are adding 1 more number to the 'sequence' 1+x+x^2 +......+x^n then + x^(n+1) not +x^(n1) thats already in there

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0what do you mean by mam?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.