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anonymous

  • one year ago

5. Triangle ABC has an angle of 90 degrees at B. Point A is on the y axis, AB is part of the line x-2y+8=0 and C is the point (6,2) (iii) Answer = AB equals the square root of 20 BC equals the square root of 20 Area of triangle equals 10 (iv) Using your answer to (iii), find the length of the perpendicular from B to AC. I don't even know where to start here, what is the method for figuring this out? And do they mean a line perpendicular to AC meeting B?

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  1. anonymous
    • one year ago
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    ok just making sure, the stuff you have for (iii) are distances you've already solved for?

  2. anonymous
    • one year ago
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    Yes, and I checked the answers at the back of my book already so they are definitely correct.

  3. anonymous
    • one year ago
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    Would it help to upload a picture of the triangle?

  4. anonymous
    • one year ago
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    yes definitely

  5. anonymous
    • one year ago
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    Ok give me a second....

  6. anonymous
    • one year ago
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  7. anonymous
    • one year ago
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    That is the triangle they have on the answers side of the book (the very first question was to draw it which i did successfully)

  8. anonymous
    • one year ago
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    awesome :) ok. so it's saying the line from AC is \(x+3y-12=0\) so we need the line perpendicular AC that passes through B.

  9. anonymous
    • one year ago
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    Did you solve for a point for B?

  10. anonymous
    • one year ago
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    The point B is at (4,6) is that what you mean?

  11. anonymous
    • one year ago
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    yes. there's a formula for this, the distance between a point and a line http://www.intmath.com/plane-analytic-geometry/perpendicular-distance-point-line.php But if you don't want to use that, we have to find the equation for the perpendicular line, then find the intersection point, then find the length of the segment

  12. anonymous
    • one year ago
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    Ok, thats great and I could use that but would that be using the answers i got in the last question?

  13. anonymous
    • one year ago
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    ok. I got you. Use the Pythagorean theorem to find the base of the triangle \[\sqrt{20}^2+\sqrt{20}^2=b^2\] Then use the formula for area of a triangle \[10=bh\] |dw:1441203786360:dw|

  14. anonymous
    • one year ago
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    wow I'm a dummy. Area of a triangle is ½bh not just bh

  15. anonymous
    • one year ago
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    you follow?

  16. anonymous
    • one year ago
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    oh good I thought I was doing something wrong, yes let me just try it quickly to make sure I understand...

  17. anonymous
    • one year ago
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    hmmmm I am getting square root of ten not just ten. My working out is: square root of 40 = b 10=1/2 x square root of 40 x h 10= square root of 10 x h square root of 10 = h

  18. anonymous
    • one year ago
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    yes, √10 is correct

  19. anonymous
    • one year ago
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    Oh sorry, have been making silly mistake with the maths all day, thank you so very much! You have helped me a lot!

  20. anonymous
    • one year ago
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    you're welcome.

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