adajiamcneal
  • adajiamcneal
help please. Angebra 2
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
adajiamcneal
  • adajiamcneal
1 Attachment
anonymous
  • anonymous
http://www.mathsisfun.com/definitions/inequality.html This should help with finding out what inequality is : )
adajiamcneal
  • adajiamcneal
i know what inequality is. . .

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
So your problem is asking you: 57 minus the variable t times 4 is greater than or equal to 13.
adajiamcneal
  • adajiamcneal
still dont know what to do
anonymous
  • anonymous
I will explain. You have to find out what T equals. So first you will have to subtract 13 from 57.
adajiamcneal
  • adajiamcneal
so would it be c ?
anonymous
  • anonymous
Not quite, because you know that four has to be multiplied by what to become 44?
anonymous
  • anonymous
to find that, divide 44 by four.
adajiamcneal
  • adajiamcneal
11. which is c
anonymous
  • anonymous
Great, so now that you know T=11, you can compare. Your answer is C. Good job!
adajiamcneal
  • adajiamcneal
thats what i said and you said i was wrong. . .
anonymous
  • anonymous
No, I just wanted to work out the whole problem first.
adajiamcneal
  • adajiamcneal
. . . how do you think i found the answer? Thank you for helping though..
anonymous
  • anonymous
You're welcome.

Looking for something else?

Not the answer you are looking for? Search for more explanations.