What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Are you trying to find the circumference or radius?
(x-h)^2 + (y-k)^2 = r^2 is the standard equation for a circle for starters.
(h,k) is the center of the circle; the point given was (-2,1) -2 is point h, and 1 is point k.
R^2 is the radius squared.
H corresponds with X and K corresponds with K for a side note.
So using the points (-2,1) and (-4,1) to find it's radius, the differences between -2 and -4 is 2 points. So 2 is the radius of the circle.
So now we got the points (-2,1) and the radius of the circle. Now all we have to do is put it in equation form.
(-2, 1) r=2 would become (x-h)^2 + (y-k)^2 = r^2.
In the end, it is (x+2)^2 + (y-1)^2=2^2