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anonymous
 one year ago
What is the general form of the equation of a circle with its center at (2, 1) and passing through (4, 1)?
anonymous
 one year ago
What is the general form of the equation of a circle with its center at (2, 1) and passing through (4, 1)?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you trying to find the circumference or radius?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(xh)^2 + (yk)^2 = r^2 is the standard equation for a circle for starters. (h,k) is the center of the circle; the point given was (2,1) 2 is point h, and 1 is point k. R^2 is the radius squared. H corresponds with X and K corresponds with K for a side note. So using the points (2,1) and (4,1) to find it's radius, the differences between 2 and 4 is 2 points. So 2 is the radius of the circle. So now we got the points (2,1) and the radius of the circle. Now all we have to do is put it in equation form. (2, 1) r=2 would become (xh)^2 + (yk)^2 = r^2. In the end, it is (x+2)^2 + (y1)^2=2^2
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