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anonymous
 one year ago
Help! Medal and Fan! :D
Which of the following statements are true?
I. The area under a normal curve is always equal to 1, no matter what the mean and standard deviation are.
II. The smaller the standard deviation of a normal curve is, the higher and narrower the graph.
III. Normal curves with different means are centered around different numbers.
anonymous
 one year ago
Help! Medal and Fan! :D Which of the following statements are true? I. The area under a normal curve is always equal to 1, no matter what the mean and standard deviation are. II. The smaller the standard deviation of a normal curve is, the higher and narrower the graph. III. Normal curves with different means are centered around different numbers.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 @dan815 @pooja195 @Hero Please Help.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino @triciaal @Kainui @KyanTheDoodle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Answer Choices: A) I and II B) I and II C) II and III D) I, II, and III E) None of the above.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0hint: the area under the gaussian or normal curve represents the total probability, and the total probability has to be equal to 1

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0I think option B should read I and III think answer I and II correct I am not sure about III

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay! So Would it be I II and III?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0i would pick D all 3 true

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0yes! I also think that all three options are true

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0different means will position the same graph left or right based on the value of the mean
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