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Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).
parallel lines will have the same slope...so we need to find the slope of 2x - 3y = -12. Now in y = mx + b form, the slope is in the m position....so we need to turn 2x - 3y = -12 into y = mx + b form. Do you know how to do that ?
Divide -12 by 2x, right?
2x - 3y = -12 --- subtract 2x from both sides -3y = -2x - 12 -- now we need to divide both sides by -3 y = 2/3x + 4 so the number in the m position, the slope, is 2/3 are you following me ?
Wait, I'm not sure I understand completely. So the first step would be 3y = -14x?
so we have to have a slope(m) of 2/3 Now we use y = mx + b slope (m) = 2/3 (-3,4)...x = -3 and y = 4 now since we have our slope and our x and y points, we need to find b, the y intercept 4 = 2/3(-3) + b 4 = -6/3 + b 4 = -2 + b 4 + 2 = b 6 = b so our parallel line is : y = 2/3x + 6 questions ?
you are making a mistake by adding unlike terms. you cannot add -2x to and -12..they are unlike terms. 2x - 3y = -12 --- subtract 2x from both sides -3y = -2x - 12 see how I did that....
oops...you cannot add -2x to -12
-3y = -2x - 12 --- now we divide both sides by -3 to get y by itself (-3/-3)y = (-2/-3)x -12/-3 y = 2/3x + 4 get it ??
ooh ok. I understand it now. Thanks!!
then you just use y = mx + b and sub in your slope and your points and solve for b, the y intercept.....just like I did above.