anonymous
  • anonymous
Medal and Fan will be given!! The length of human pregnancies varies according to an approximately normal distribution with a mean of 266 days and variance of 256 days. How long are the longest 2.5% of all pregnancies? (Explanation question. No multiple Choice) Please help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@pooja195 @dan815 @ganeshie8 @Hero @Kainui @kiamousekia @Howard-Wolowitz
anonymous
  • anonymous
@Abhisar Please Help.
anonymous
  • anonymous
@Abhisar Can you please help. This is my last question.

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anonymous
  • anonymous
need help please @Michele_Laino
Michele_Laino
  • Michele_Laino
here we have to refer to the "erf" function
anonymous
  • anonymous
Okay. That is what I am confused on... @Michele_Laino
Michele_Laino
  • Michele_Laino
the standard deviation, of your distribution, is: \[\Large \sigma = \sqrt {256} = 16\]
anonymous
  • anonymous
Okay. I got it so far @Michele_Laino
anonymous
  • anonymous
So now what? @Michele_Laino
Michele_Laino
  • Michele_Laino
please wait, I'm working on your question...
anonymous
  • anonymous
Oh yeah sure. Take your time :D @Michele_Laino
Michele_Laino
  • Michele_Laino
I think that your problem requests for this value: |dw:1441213069159:dw|
Michele_Laino
  • Michele_Laino
from the table of the "erf" function we get: \[\large N = 266 + 1.96 \cdot \sigma = 266 + 1.96 \cdot 16 = 297.36 \cong 297\]
anonymous
  • anonymous
Okay so is that our final answer though? 297? @Michele_Laino
Michele_Laino
  • Michele_Laino
yes! I think so!
anonymous
  • anonymous
Oh my god! Thank you so much! That was very hard but you made it so easy! Thank you! Fan and medal! :) @Michele_Laino
Michele_Laino
  • Michele_Laino
:)
Michele_Laino
  • Michele_Laino
please wait I have a doubt: maybe the requested reasoning can be this: |dw:1441214281328:dw| so we have: \[\Large 266 + 2.24 \cdot 16 = 301.84 \cong 302\]

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