anonymous
  • anonymous
Medal and Fan will be given!! The length of human pregnancies varies according to an approximately normal distribution with a mean of 266 days and variance of 256 days. How long are the longest 2.5% of all pregnancies? (Explanation question. No multiple Choice) Please help!
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
anonymous
  • anonymous
@Abhisar Please Help.
anonymous
  • anonymous
@Abhisar Can you please help. This is my last question.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
need help please @Michele_Laino
Michele_Laino
  • Michele_Laino
here we have to refer to the "erf" function
anonymous
  • anonymous
Okay. That is what I am confused on... @Michele_Laino
Michele_Laino
  • Michele_Laino
the standard deviation, of your distribution, is: \[\Large \sigma = \sqrt {256} = 16\]
anonymous
  • anonymous
Okay. I got it so far @Michele_Laino
anonymous
  • anonymous
So now what? @Michele_Laino
Michele_Laino
  • Michele_Laino
please wait, I'm working on your question...
anonymous
  • anonymous
Oh yeah sure. Take your time :D @Michele_Laino
Michele_Laino
  • Michele_Laino
I think that your problem requests for this value: |dw:1441213069159:dw|
Michele_Laino
  • Michele_Laino
from the table of the "erf" function we get: \[\large N = 266 + 1.96 \cdot \sigma = 266 + 1.96 \cdot 16 = 297.36 \cong 297\]
anonymous
  • anonymous
Okay so is that our final answer though? 297? @Michele_Laino
Michele_Laino
  • Michele_Laino
yes! I think so!
anonymous
  • anonymous
Oh my god! Thank you so much! That was very hard but you made it so easy! Thank you! Fan and medal! :) @Michele_Laino
Michele_Laino
  • Michele_Laino
:)
Michele_Laino
  • Michele_Laino
please wait I have a doubt: maybe the requested reasoning can be this: |dw:1441214281328:dw| so we have: \[\Large 266 + 2.24 \cdot 16 = 301.84 \cong 302\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.