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anonymous

  • one year ago

Medal and Fan will be given!! The length of human pregnancies varies according to an approximately normal distribution with a mean of 266 days and variance of 256 days. How long are the longest 2.5% of all pregnancies? (Explanation question. No multiple Choice) Please help!

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  1. anonymous
    • one year ago
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    @pooja195 @dan815 @ganeshie8 @Hero @Kainui @kiamousekia @Howard-Wolowitz

  2. anonymous
    • one year ago
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    @Abhisar Please Help.

  3. anonymous
    • one year ago
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    @Abhisar Can you please help. This is my last question.

  4. anonymous
    • one year ago
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    need help please @Michele_Laino

  5. Michele_Laino
    • one year ago
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    here we have to refer to the "erf" function

  6. anonymous
    • one year ago
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    Okay. That is what I am confused on... @Michele_Laino

  7. Michele_Laino
    • one year ago
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    the standard deviation, of your distribution, is: \[\Large \sigma = \sqrt {256} = 16\]

  8. anonymous
    • one year ago
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    Okay. I got it so far @Michele_Laino

  9. anonymous
    • one year ago
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    So now what? @Michele_Laino

  10. Michele_Laino
    • one year ago
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    please wait, I'm working on your question...

  11. anonymous
    • one year ago
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    Oh yeah sure. Take your time :D @Michele_Laino

  12. Michele_Laino
    • one year ago
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    I think that your problem requests for this value: |dw:1441213069159:dw|

  13. Michele_Laino
    • one year ago
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    from the table of the "erf" function we get: \[\large N = 266 + 1.96 \cdot \sigma = 266 + 1.96 \cdot 16 = 297.36 \cong 297\]

  14. anonymous
    • one year ago
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    Okay so is that our final answer though? 297? @Michele_Laino

  15. Michele_Laino
    • one year ago
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    yes! I think so!

  16. anonymous
    • one year ago
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    Oh my god! Thank you so much! That was very hard but you made it so easy! Thank you! Fan and medal! :) @Michele_Laino

  17. Michele_Laino
    • one year ago
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    :)

  18. Michele_Laino
    • one year ago
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    please wait I have a doubt: maybe the requested reasoning can be this: |dw:1441214281328:dw| so we have: \[\Large 266 + 2.24 \cdot 16 = 301.84 \cong 302\]

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