A community for students.
Here's the question you clicked on:
 0 viewing
Destinyyyy
 one year ago
Need two problems checked...
Destinyyyy
 one year ago
Need two problems checked...

This Question is Closed

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Solve the absolute value inequality. 36< {2x+18/5} +9/5 {} absolute value

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1180/5 <{2x+ 18/5} 2x+18/5> 180/5 2x+ 18/5< 180/5

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1I got x> 81/5 x< 99/5

linn99123
 one year ago
Best ResponseYou've already chosen the best response.2okay so whats ur answer for number 1?

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1I posted both of my answers above.

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Im not sure what you mean by number one. I only posted one question.

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0looks like you know the way to solve them, not sure about the numbers

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0and i am sure about my answer

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1\(2x+18/5+9/5>36 \) \(2x+18/5>189/5 \leftarrow \text{one correction here}\)

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Where are you getting 189 from???

DanJS
 one year ago
Best ResponseYou've already chosen the best response.036  (9/5) = 171/5 for the first thing

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.136+9/5=189/5

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Omg... 36 *5= 180 .. I forgot to minus the 9 .

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1eh should be 1809 i added them

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1it is ok well make mistakes

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1but the she got the point

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Now I have 2x> 153/5 2x < 153/5

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1yah yo got the point of this just made some few error just recheck for certainty

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1you know how this works that's what is important

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1i got the same result you should be good to go

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Okay. But now im stuck.. 2 cant be divided into these. And my last problem like this just divided the top number by 2

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1multiply by 1/2 and switch the sign > to < and < to >

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1if you multiply by negative you should change the inequality

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Uh? I know what the final answer is because I looked it up on mathway... But dont get how I go from what I have to it.

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@Destinyyyy u have find it 171/10< x<153/10 i didnt focus first time

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1The answer is ( infinity sign, 153/10) u (189/10 , infinity sign)

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0yup i was wrong its 189/10 sorry

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0i forget add 18/2 only sorry

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1How do I get from 2x> 153/5 and 2x< 153/5 to the final answer

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1i told you to multiply by 1/2 both sides

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1first one x<153/10 see the inequality changed

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1second x>153/10

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0not that u have 2x>153/5  2x<153/5 x<153/10 @Destinyyyy

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1actually you made a mistake somewhere for the scond

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1it should not be 2x<153/5

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0this is not  its just Arrow

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Then Id have to change the denominators to 10... 306/10 5/10 .. Do I minus, divide, multiple?

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1What are you talking about? Its over 5 not 10

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0not that u have (2x>153/5)  (2x<153/5) (x<153/10 ) @xapproachesinfinity this what i mean

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1the second should have been 2x<189/5 then x>189/10

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1that what i meant she made a mistake in calculations

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1after that just read what x<153/10 and x>189/10 mean in interval nottion

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1you should get that same answer you have by mathway

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1over 10 my bad

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1OMG. Seriously. Im an still at 2x> 153/5 and 2x< 153/5

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1I dont understand your multiple by 1/2.

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1you need to isolate x right

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1so we multiply by a minus sign which switches the inequality then we multiply by 1/2 to get rid of 2

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1it is like you do with equation to islote the unknown

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Still dont understand.

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1how would you solve 2x=4

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Divide both sides by 2.

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1so same thing divide the inequality both sides by 2

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1that is the same as multiplying out by 1/2 hahaha

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Okay. Like I said before its not possible. It gives a decimal.... K? So then Id have to change both denominators to 10.

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1why decimal ? you get 153/5x2

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1i dont see where do you get decimal?

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1What are you talking about? 153 divided by 2= 76.5

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1why you need to divide? leave it 153/5x2=153/10

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0\[2x+\frac{ 18 }{ 2 }>\frac{ 171 }{ 5 }\] \[\frac{ 171}{ 5 }>2x+\frac{ 18 }{ 2 }>\frac{ 171 }{ 5}\] \[\frac{ 17118 }{ 5 }>2x>\frac{ 17118 }{ 5}\] \[\frac{ 189 }{ 5}>2x>\frac{ 153 }{ 5 }\] \[\frac{ 153 }{ 10 }>x>\frac{ 189 }{ 10 }\] @xapproachesinfinity could u check my mistake @Destinyyyy this is real solution

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1you making this hard on youself

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0cuz i think this is right answer @xapproachesinfinity

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1No im not. You are making this impossible to understand. Ive waited 2 hours for help and now Im just confused. Normally you just divide it. And instead im suppose to multiple it. But all you did was change the denominator. Why???

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1yes your answer is good @dinamix

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1You said to multiply by 1/2 so I asked about changing both denominator to 10. And both times you did not respond. So im just suppose to do 5*2= 10 ?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1heheheh thanks i thought i made efforts to show you

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1I understand the first one. Now what about the other one.

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@xapproachesinfinity ty @Destinyyyy what u didnt understand we can help u

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1ok dinamix take over i have to go

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@xapproachesinfinity plz i dont know how to explain

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0its hard to expalin idea for me @xapproachesinfinity this problem of me

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@Destinyyyy what i show u

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Can you just show me how you went from 2x< 153/5 to 189/10

dinamix
 one year ago
Best ResponseYou've already chosen the best response.02x>153/5 to x<153/10 right ?

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0that what u mean or what

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1If I go off from what both of you said before by just multiplying by 1/2 then Ill just get 153/10 which is not the correct answer. Which also makes me think how you said to solve the first one is not the correct way to solve it.

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1The fist sign goes < not >

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.12x< 153/5 to 189/10

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0\[2x+\frac{ 18 }{ 5} > 171/5\] and \[(2x+\frac{ 18 }{ 5 })>171/5 \]\[\frac{ 171 }{ 5 } >2x+\frac{ 18 }{ 5 }>\frac{ 171 }{ 5}\]

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@Destinyyyy its 2 equation i make it only one did u understand now

freckles
 one year ago
Best ResponseYou've already chosen the best response.136< 2x+18/5 +9/5 Just because I like to write the absolute value expression first then the inequality thingy.. \[2x+\frac{18}{5}+\frac{9}{5}>36 \\ \text{ so you subtracted } \frac{9}{5} \text{ on both sides } \\ 2x+\frac{18}{5}>36\frac{9}{5} \\ 2x+\frac{18}{5}> \frac{1809}{5} \\ 2x+\frac{18}{5} >\frac{171}{5} \\ \text{ now since this is a greater than we have a union } \\ \text{ that is we have } 2x+\frac{18}{5}<\frac{171}{5} \text{ or } 2x+\frac{18}{5}>\frac{171}{5} \\ \text{ for both inequalities subtract }\frac{18}{5} \text{ on both sides } \\ 2x<\frac{171}{5}\frac{18}{5} \text{ or } 2x> \frac{171}{5}\frac{18}{5} \\ \text{ simplifying right hand sides } \\ 2x <\frac{189}{5} \text{ or } 2x >\frac{153}{5} \\ \text{ now you can say divide both sides by 2 } \\ \text{ or equivalently say multiply both sides by } \frac{1}{2} \\ \text{ this is the same meaning just different saying } \] \[\frac{1}{2} \cdot (2x)>\frac{1}{2}(\frac{189}{5}) \text{ change direction of inequality symbol } \\ \text{ since I multiplied both sides by a negative } \\ x>\frac{189}{10} \\ \text{ now the other inequality } \\ \frac{1}{2}(2x)<\frac{1}{2}(\frac{153}{5}) \\ x<\frac{153}{10}\] so put the two pieces together and put or between them

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@freckles like my steps lol

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[x<\frac{153}{10} \text{ or } x>\frac{189}{10}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1your solution seems to suggest 171 is greater than 171 since it says 171/5>171/5 @dinamix

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@freckles but why we get same result

freckles
 one year ago
Best ResponseYou've already chosen the best response.1no I didn't get 171>171 because this is not true

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Omg thank you @freckles I completely understood everything you said. And I saw where I messed up. I did write down the  for 171/5 so when I minused the 18 I had the wrong answer. Now I have the correct one and understand how to solve the ending.

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0but @freckles look the last i get 153/10 >x or x>189/10 look

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1And all that turns into ( infinity sign, 153/10) u (189/10, infinity sign)

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1@freckles Can you check one more? I know that my answer is wrong, but im not sure how it is.

freckles
 one year ago
Best ResponseYou've already chosen the best response.1alright one more and then I eat

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Okay... Use interval notation to express the solution set and graph the solution set on a number line. x/4  1/5 </ x/5 +1

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{x}{4}\frac{1}{5} \le \frac{x}{5}+1\]

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1I got x</ 2 ( infinity sign, 2] But it says im wrong Yes thats correct

freckles
 one year ago
Best ResponseYou've already chosen the best response.1so I retriceumed you subtracted x/5 on both sides and added 1/5 on both sides?

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1My example had me plus 1/5 to both sides. So I have x/4 </ x/5 +1 +1/5 Then add the +1 and 1/5 together x/4 </ x/5 +6/5

freckles
 one year ago
Best ResponseYou've already chosen the best response.1@Destinyyyy if you don't like the fractions before moving anything you can multiply both sides by 4*5=20

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[(20)(\frac{x}{4}\frac{1}{5} ) \le 20(\frac{x}{5}+1) \\ \frac{20}{4}x\frac{20}{5} \le \frac{20}{5}x+20 \\ 5x4 \le 4x+20\] this might make it easier for you

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@freckles ty for help her or him anyway , i know the answer but i dont how eplain idea this my problem

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1( infinity sign, 24]

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0yup @Destinyyyy this the answer hreat now u understand

freckles
 one year ago
Best ResponseYou've already chosen the best response.1yep now if you didn't do the whole canceling fraction thing... \[\frac{x}{4}\frac{1}{5} \le \frac{x}{5}+1 \\ \text{ subtract } \frac{x}{5} \text{ on both sides } \\ \frac{x}{4} \frac{x}{5}\frac{1}{5} \le 1 \\ \text{ now add } \frac{1}{5} \text{ on both sides } \\ \frac{x}{4} \frac{x}{5} \le 1+\frac{1}{5} \\ \\ \text{ find common denominators } \\ \frac{5x4x}{20} \le \frac{5+1}{5} \\ \frac{1x}{20} \le \frac{6}{5} \\ \frac{x}{20} \le \frac{6}{5} \\ \text{ multiply both side by } 20 \\ x \le \frac{6(20)}{5} \\ x \le 6 \cdot \frac{20}{5} \\ x \le 6 (4) \\ x \le 24\] just so you know how it looks without removing fractions first

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@Destinyyyy i find it without use pain last question ;D

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0@Destinyyyy and u can will be like that

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1The example I followed didnt show me like that.. It did x/4 </ x/5 +1 +1/5 x/4 </ x+5 +6/5 x/4 x/5 </ 6/5 4xx/5 </ 6/5 4xx </ 6 3x</ 6 x</2

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1So I would have gotten the right answer if it had told me to do over 20 instead of over 5.. Which I thought was weird. Thank you for helping! @freckles

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0u make mistake in line 4

Destinyyyy
 one year ago
Best ResponseYou've already chosen the best response.1Yeah I know that. But that's what the example said to do so I did.

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 5x 4x}{ 20 }\]

dinamix
 one year ago
Best ResponseYou've already chosen the best response.0=\[\frac{ x }{ 4}\frac{ x }{ 5 }\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.