Destinyyyy
  • Destinyyyy
Need two problems checked...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Destinyyyy
  • Destinyyyy
Solve the absolute value inequality. 36< {-2x+18/5} +9/5 {} absolute value
Destinyyyy
  • Destinyyyy
180/5 <{-2x+ 18/5} -2x+18/5> 180/5 -2x+ 18/5< -180/5
Destinyyyy
  • Destinyyyy
I got-- x> -81/5 x< 99/5

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More answers

linn99123
  • linn99123
okay so whats ur answer for number 1?
Destinyyyy
  • Destinyyyy
I posted both of my answers above.
Destinyyyy
  • Destinyyyy
Im not sure what you mean by number one. I only posted one question.
DanJS
  • DanJS
looks like you know the way to solve them, not sure about the numbers
dinamix
  • dinamix
and i am sure about my answer
Destinyyyy
  • Destinyyyy
Okay
xapproachesinfinity
  • xapproachesinfinity
\(|-2x+18/5|+9/5>36 \) \(|-2x+18/5|>189/5 \leftarrow \text{one correction here}\)
Destinyyyy
  • Destinyyyy
Where are you getting 189 from???
DanJS
  • DanJS
36 - (9/5) = 171/5 for the first thing
xapproachesinfinity
  • xapproachesinfinity
36+9/5=189/5
Destinyyyy
  • Destinyyyy
Omg... 36 *5= 180 .. I forgot to minus the 9 -.-
xapproachesinfinity
  • xapproachesinfinity
eh should be 180-9 i added them
xapproachesinfinity
  • xapproachesinfinity
it is ok well make mistakes
xapproachesinfinity
  • xapproachesinfinity
we all*
xapproachesinfinity
  • xapproachesinfinity
but the she got the point
Destinyyyy
  • Destinyyyy
Now I have -2x> 153/5 -2x < -153/5
xapproachesinfinity
  • xapproachesinfinity
yah yo got the point of this just made some few error just recheck for certainty
xapproachesinfinity
  • xapproachesinfinity
you know how this works that's what is important
xapproachesinfinity
  • xapproachesinfinity
i got the same result you should be good to go
Destinyyyy
  • Destinyyyy
Okay. But now im stuck.. -2 cant be divided into these. And my last problem like this just divided the top number by -2
xapproachesinfinity
  • xapproachesinfinity
multiply by -1/2 and switch the sign > to < and < to >
xapproachesinfinity
  • xapproachesinfinity
if you multiply by negative you should change the inequality
Destinyyyy
  • Destinyyyy
Uh? I know what the final answer is because I looked it up on mathway... But dont get how I go from what I have to it.
dinamix
  • dinamix
@Destinyyyy u have find it 171/10< x<-153/10 i didnt focus first time
Destinyyyy
  • Destinyyyy
The answer is (- infinity sign, -153/10) u (189/10 , infinity sign)
dinamix
  • dinamix
yup i was wrong its 189/10 sorry
dinamix
  • dinamix
i forget add 18/2 only sorry
Destinyyyy
  • Destinyyyy
How do I get from -2x> 153/5 and -2x< -153/5 to the final answer
xapproachesinfinity
  • xapproachesinfinity
i told you to multiply by -1/2 both sides
xapproachesinfinity
  • xapproachesinfinity
first one x<-153/10 see the inequality changed
xapproachesinfinity
  • xapproachesinfinity
second x>153/10
dinamix
  • dinamix
not that u have -2x>153/5 ------ 2x<-153/5 -----x<-153/10 @Destinyyyy
xapproachesinfinity
  • xapproachesinfinity
actually you made a mistake somewhere for the scond
dinamix
  • dinamix
i fix it now
xapproachesinfinity
  • xapproachesinfinity
it should not be -2x<-153/5
dinamix
  • dinamix
this is not - its just Arrow
Destinyyyy
  • Destinyyyy
Then Id have to change the denominators to 10... 306/10 5/10 .. Do I minus, divide, multiple?
Destinyyyy
  • Destinyyyy
What are you talking about? Its over 5 not 10
dinamix
  • dinamix
not that u have (-2x>153/5) ------ (2x<-153/5) -----(x<-153/10 ) @xapproachesinfinity this what i mean
xapproachesinfinity
  • xapproachesinfinity
the second should have been -2x<-189/5 then x>189/10
xapproachesinfinity
  • xapproachesinfinity
that what i meant she made a mistake in calculations
xapproachesinfinity
  • xapproachesinfinity
after that just read what x<-153/10 and x>189/10 mean in interval nottion
xapproachesinfinity
  • xapproachesinfinity
you should get that same answer you have by mathway
xapproachesinfinity
  • xapproachesinfinity
over 10 my bad
Destinyyyy
  • Destinyyyy
OMG. Seriously. Im an still at -2x> 153/5 and -2x< -153/5
Destinyyyy
  • Destinyyyy
I dont understand your multiple by -1/2.
xapproachesinfinity
  • xapproachesinfinity
you need to isolate x right
xapproachesinfinity
  • xapproachesinfinity
so we multiply by a minus sign which switches the inequality then we multiply by 1/2 to get rid of 2
xapproachesinfinity
  • xapproachesinfinity
it is like you do with equation to islote the unknown
Destinyyyy
  • Destinyyyy
...
Destinyyyy
  • Destinyyyy
Still dont understand.
xapproachesinfinity
  • xapproachesinfinity
how would you solve 2x=4
Destinyyyy
  • Destinyyyy
Divide both sides by 2.
xapproachesinfinity
  • xapproachesinfinity
so same thing divide the inequality both sides by 2
xapproachesinfinity
  • xapproachesinfinity
that is the same as multiplying out by 1/2 hahaha
Destinyyyy
  • Destinyyyy
Okay. Like I said before its not possible. It gives a decimal.... K? So then Id have to change both denominators to 10.
xapproachesinfinity
  • xapproachesinfinity
why decimal ? you get -153/5x2
xapproachesinfinity
  • xapproachesinfinity
i dont see where do you get decimal?
Destinyyyy
  • Destinyyyy
What are you talking about? 153 divided by -2= -76.5
xapproachesinfinity
  • xapproachesinfinity
why you need to divide? leave it 153/5x2=153/10
dinamix
  • dinamix
\[|-2x+\frac{ 18 }{ 2 }|>\frac{ 171 }{ 5 }\] \[\frac{ -171}{ 5 }>-2x+\frac{ 18 }{ 2 }>\frac{ 171 }{ 5}\] \[\frac{ -171-18 }{ 5 }>-2x>\frac{ 171-18 }{ 5}\] \[\frac{ -189 }{ 5}>-2x>\frac{ 153 }{ 5 }\] \[-\frac{ 153 }{ 10 }>x>\frac{ 189 }{ 10 }\] @xapproachesinfinity could u check my mistake @Destinyyyy this is real solution
xapproachesinfinity
  • xapproachesinfinity
you making this hard on youself
dinamix
  • dinamix
cuz i think this is right answer @xapproachesinfinity
Destinyyyy
  • Destinyyyy
No im not. You are making this impossible to understand. Ive waited 2 hours for help and now Im just confused. Normally you just divide it. And instead im suppose to multiple it. But all you did was change the denominator. Why???
xapproachesinfinity
  • xapproachesinfinity
yes your answer is good @dinamix
Destinyyyy
  • Destinyyyy
You said to multiply by 1/2 so I asked about changing both denominator to 10. And both times you did not respond. So im just suppose to do 5*2= 10 ?
xapproachesinfinity
  • xapproachesinfinity
heheheh thanks i thought i made efforts to show you
Destinyyyy
  • Destinyyyy
I understand the first one. Now what about the other one.
dinamix
  • dinamix
@xapproachesinfinity ty @Destinyyyy what u didnt understand we can help u
xapproachesinfinity
  • xapproachesinfinity
ok dinamix take over i have to go
dinamix
  • dinamix
@xapproachesinfinity plz i dont know how to explain
Destinyyyy
  • Destinyyyy
Try showing me?
dinamix
  • dinamix
its hard to expalin idea for me @xapproachesinfinity this problem of me
dinamix
  • dinamix
@Destinyyyy what i show u
Destinyyyy
  • Destinyyyy
Can you just show me how you went from -2x< -153/5 to 189/10
dinamix
  • dinamix
-2x>153/5 to x<-153/10 right ?
dinamix
  • dinamix
that what u mean or what
Destinyyyy
  • Destinyyyy
If I go off from what both of you said before by just multiplying by -1/2 then Ill just get 153/10 which is not the correct answer. Which also makes me think how you said to solve the first one is not the correct way to solve it.
Destinyyyy
  • Destinyyyy
The fist sign goes < not >
Destinyyyy
  • Destinyyyy
-2x< -153/5 to 189/10
dinamix
  • dinamix
\[-2x+\frac{ 18 }{ 5} > 171/5\] and \[-(-2x+\frac{ 18 }{ 5 })>171/5 \]\[\frac{ -171 }{ 5 } >-2x+\frac{ 18 }{ 5 }>\frac{ 171 }{ 5}\]
dinamix
  • dinamix
@Destinyyyy its 2 equation i make it only one did u understand now
freckles
  • freckles
36< |-2x+18/5| +9/5 Just because I like to write the absolute value expression first then the inequality thingy.. \[|-2x+\frac{18}{5}|+\frac{9}{5}>36 \\ \text{ so you subtracted } \frac{9}{5} \text{ on both sides } \\ |-2x+\frac{18}{5}|>36-\frac{9}{5} \\ |-2x+\frac{18}{5}|> \frac{180-9}{5} \\ |-2x+\frac{18}{5}| >\frac{171}{5} \\ \text{ now since this is a greater than we have a union } \\ \text{ that is we have } -2x+\frac{18}{5}<-\frac{171}{5} \text{ or } -2x+\frac{18}{5}>\frac{171}{5} \\ \text{ for both inequalities subtract }\frac{18}{5} \text{ on both sides } \\ -2x<\frac{-171}{5}-\frac{18}{5} \text{ or } -2x> \frac{171}{5}-\frac{18}{5} \\ \text{ simplifying right hand sides } \\ -2x <\frac{-189}{5} \text{ or } -2x >\frac{153}{5} \\ \text{ now you can say divide both sides by -2 } \\ \text{ or equivalently say multiply both sides by } \frac{-1}{2} \\ \text{ this is the same meaning just different saying } \] \[\frac{-1}{2} \cdot (-2x)>\frac{-1}{2}(\frac{-189}{5}) \text{ change direction of inequality symbol } \\ \text{ since I multiplied both sides by a negative } \\ x>\frac{189}{10} \\ \text{ now the other inequality } \\ \frac{-1}{2}(-2x)<\frac{-1}{2}(\frac{153}{5}) \\ x<\frac{-153}{10}\] so put the two pieces together and put or between them
dinamix
  • dinamix
@freckles like my steps lol
freckles
  • freckles
\[x<\frac{-153}{10} \text{ or } x>\frac{189}{10}\]
freckles
  • freckles
your solution seems to suggest -171 is greater than 171 since it says -171/5>171/5 @dinamix
dinamix
  • dinamix
@freckles but why we get same result
freckles
  • freckles
no I didn't get -171>171 because this is not true
Destinyyyy
  • Destinyyyy
Omg thank you @freckles I completely understood everything you said. And I saw where I messed up. I did write down the - for -171/5 so when I minus-ed the 18 I had the wrong answer. Now I have the correct one and understand how to solve the ending.
dinamix
  • dinamix
but @freckles look the last i get -153/10 >x or x>189/10 look
Destinyyyy
  • Destinyyyy
And all that turns into (- infinity sign, -153/10) u (189/10, infinity sign)
Destinyyyy
  • Destinyyyy
@freckles Can you check one more? I know that my answer is wrong, but im not sure how it is.
freckles
  • freckles
alright one more and then I eat
Destinyyyy
  • Destinyyyy
Okay... Use interval notation to express the solution set and graph the solution set on a number line. x/4 - 1/5
freckles
  • freckles
\[\frac{x}{4}-\frac{1}{5} \le \frac{x}{5}+1\]
freckles
  • freckles
is that correct
Destinyyyy
  • Destinyyyy
I got x
freckles
  • freckles
so I retriceumed you subtracted x/5 on both sides and added 1/5 on both sides?
freckles
  • freckles
assumed*
dinamix
  • dinamix
x<24 i find it
Destinyyyy
  • Destinyyyy
My example had me plus 1/5 to both sides. So I have x/4
freckles
  • freckles
@Destinyyyy if you don't like the fractions before moving anything you can multiply both sides by 4*5=20
freckles
  • freckles
\[(20)(\frac{x}{4}-\frac{1}{5} ) \le 20(\frac{x}{5}+1) \\ \frac{20}{4}x-\frac{20}{5} \le \frac{20}{5}x+20 \\ 5x-4 \le 4x+20\] this might make it easier for you
Destinyyyy
  • Destinyyyy
x
dinamix
  • dinamix
@freckles ty for help her or him anyway , i know the answer but i dont how eplain idea this my problem
Destinyyyy
  • Destinyyyy
(- infinity sign, 24]
Destinyyyy
  • Destinyyyy
Im a her....
dinamix
  • dinamix
yup @Destinyyyy this the answer hreat now u understand
dinamix
  • dinamix
ok i was joke only
freckles
  • freckles
yep now if you didn't do the whole canceling fraction thing... \[\frac{x}{4}-\frac{1}{5} \le \frac{x}{5}+1 \\ \text{ subtract } \frac{x}{5} \text{ on both sides } \\ \frac{x}{4} -\frac{x}{5}-\frac{1}{5} \le 1 \\ \text{ now add } \frac{1}{5} \text{ on both sides } \\ \frac{x}{4} -\frac{x}{5} \le 1+\frac{1}{5} \\ \\ \text{ find common denominators } \\ \frac{5x-4x}{20} \le \frac{5+1}{5} \\ \frac{1x}{20} \le \frac{6}{5} \\ \frac{x}{20} \le \frac{6}{5} \\ \text{ multiply both side by } 20 \\ x \le \frac{6(20)}{5} \\ x \le 6 \cdot \frac{20}{5} \\ x \le 6 (4) \\ x \le 24\] just so you know how it looks without removing fractions first
dinamix
  • dinamix
@Destinyyyy i find it without use pain last question ;D
dinamix
  • dinamix
@Destinyyyy and u can will be like that
Destinyyyy
  • Destinyyyy
The example I followed didnt show me like that.. It did x/4
dinamix
  • dinamix
pen*
Destinyyyy
  • Destinyyyy
So I would have gotten the right answer if it had told me to do over 20 instead of over 5.. Which I thought was weird. Thank you for helping! @freckles
freckles
  • freckles
np i will eat now
dinamix
  • dinamix
u make mistake in line 4
Destinyyyy
  • Destinyyyy
Yeah I know that. But that's what the example said to do so I did.
dinamix
  • dinamix
\[\frac{ 5x -4x}{ 20 }\]
dinamix
  • dinamix
=\[\frac{ x }{ 4}-\frac{ x }{ 5 }\]

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