llroberts43
  • llroberts43
How do I find the equation of a line that passes through (-2,-1) and (-1, -6)? I have to put it in slope intercept form
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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calculusxy
  • calculusxy
\[\large y = mx+b\] m = slope b = y-intercept
calculusxy
  • calculusxy
First, I suggest you to figure out the slope.
calculusxy
  • calculusxy
Do you know how to?

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llroberts43
  • llroberts43
the slope is -5
calculusxy
  • calculusxy
Okay so we will go with that.
calculusxy
  • calculusxy
Now that we have the slope as -5, we can substitute m for that. \[\large y = -5x + b\] Usually, in this case, what I would do is choose a coordinate from the two that are already given. So we will use (-2,-1)... As you can see that with -5 there is a "x". We will substitute that x with -2 and the y before the equal sign will be replaced with the y-coordinate (or -1). \[\large -1 = -5(-2) + b\] Now you need to solve for b.
llroberts43
  • llroberts43
So I'm multiplying -5 and -2 and that gives me 10
calculusxy
  • calculusxy
yes go on...
llroberts43
  • llroberts43
I don't know how to solve for b...I don't know what to do next
calculusxy
  • calculusxy
\[\large -1 = 10 + b\] \[\large -1 - 10 = 10 - 10 + b\] \[\large -11 = b\] Let's check this now: \[\large -1 = -5(-2) - 11 => -1 = 10 - 11 => -1 = -1\]
calculusxy
  • calculusxy
\[\large -6 = -5(-1) -11 => -6 = 5 - 11 => -6 = -6\]
calculusxy
  • calculusxy
So your slope intercept form is \[\large y = -5x - 11\]
calculusxy
  • calculusxy
Do you understand how I got it? @llroberts43
llroberts43
  • llroberts43
sorry I'm at work...trying to get off the phone so I can look
llroberts43
  • llroberts43
Ok, you subtracted 10 from both sides and that gave you the -11
calculusxy
  • calculusxy
yes
calculusxy
  • calculusxy
we needed to isolate b
llroberts43
  • llroberts43
Thank you. I have a final on this stuff today and I'm just stressed out. I don't remember doing this stuff
calculusxy
  • calculusxy
It's okay .. take a deep breath and you will be fine.. just review the work that I did in here.
llroberts43
  • llroberts43
I will. thanks again

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