A community for students.
Here's the question you clicked on:
 0 viewing
zarkam21
 one year ago
Help please
zarkam21
 one year ago
Help please

This Question is Closed

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1each time 2 outcomes are possible, namely head and tail

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0so for part one, it would be 2*2*2*2=8?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1please wait: it is 2*2*2*2=16

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0yeah but isn't it a total of 8 outcomes

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1more precisely: we have 2 possible outcomes for each flip, so when we multiply, we get: \[\Large 2 \times 2 \times 2 \times 2 = 16\] that number expresses the possible outcomes

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1if we add: 2+2+2+2 we get 8 nevertheless that number is not interesting for your exercise

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0okay so 2*2*2*2=16 :]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1correct! I'm sorry for my previous error

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0Let's move on to part II

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here we have to do the subsequent reasoning: lets suppose to start from a head (H) then the next flip can be another head or a tail, so we have these outcomes: \[\Large \begin{gathered} HH \hfill \\ HT \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1whereas if we start from a tail (T), then next flip can be another tail or a head, so we get these other possible outcomes: \[\Large \begin{gathered} TH \hfill \\ TT \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1in total we got these four outcomes: \[\Large \begin{gathered} 1)HH \hfill \\ 2)HT \hfill \\ 3)TH \hfill \\ 4)TT \hfill \\ \end{gathered} \]

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0So that is part II? HH,HT, TH, and TT

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1no, we have to finish :)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1next, let's start from the outcome 1) then next flip can be a head or a tail, so we get these outcomes: \[\Large \begin{gathered} HHH \hfill \\ HHT \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now, let's start from outcome 2), then next flip can be a head ot a tail, so we get these new outcomes: \[\Large \begin{gathered} HTH \hfill \\ HTT \hfill \\ \end{gathered} \]

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0Yes, :} Would the next be, THH and THT

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0and I'm guessing the next is TTH and TTT

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1and the next two new outcomes are: \[\Large \begin{gathered} TTT \hfill \\ TTH \hfill \\ \end{gathered} \] since I have started from outcome 4)

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0Does it matter what order?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1no, the order of the outcomes, is not important so, in total we got these outcomes: \[\Large \begin{gathered} a)HHH \hfill \\ b)HHT \hfill \\ c)HTH \hfill \\ d)HTT \hfill \\ e)THT \hfill \\ f)THH \hfill \\ g)TTT \hfill \\ h)TTH \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now, we have to start from outcome a) and, with the same procedure we get these two new outcomes: \[\Large \begin{gathered} HHHH \hfill \\ HHHT \hfill \\ \end{gathered} \]

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0and then it would be HHTH and HHTT

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1starting from outcome b) I get these ones: \[\Large \begin{gathered} HHTH \hfill \\ HHTT \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1and we have to repeat the same procedure for the remaining outcomes c), d), e), f), g) and H)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so we get these outcomes: \[\Large \begin{gathered} 1)HHHH \hfill \\ 2)HHHT \hfill \\ 3)HHTH \hfill \\ 4)HHTT \hfill \\ 5)HTHH \hfill \\ 6)HTHT \hfill \\ 7)HTTT \hfill \\ 8)HTTH \hfill \\ 9)THTT \hfill \\ 10)THTH \hfill \\ 11)THHT \hfill \\ 12)THHH \hfill \\ 13)TTTT \hfill \\ 14)TTTH \hfill \\ 15)TTHT \hfill \\ 16)TTHH \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1that is the answer for part II

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1as you can see there are 16 possible outcomes, namely the number which we have computed in part I

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now, for part III, we have highlight those outcomes which contains two T, namely TT

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1how many outcomes contain two (T)

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.02 or more or just two

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I got six outcomes, precisely the subsequent outcomes: #4, #6, #8 ,#10, #11, #16

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so the probability to have two flips which comes up with (T) is: p=favorable outcomes/possible outcomes=6/16 am I right?

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0But would't 6/16 be reduced

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1it is: \[\Large p = \frac{6}{{16}} = \frac{3}{8}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1for part III is right!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here we have to highlight those outcomes which contain three (H). How many outcomes do contain three (H) ?

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0Okay so #2, #3, #5, and #12

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1correct! we have 5 outcomes, so the requested probability, is: p=favorable outcomes/possible outcomes=\[\Large p = \frac{5}{{16}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1oops.. sorry we have 4 outcomes, so the requested probability is: \[\Large p = \frac{4}{{16}} = \frac{1}{4}\]

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.0Thank you sooo much !!!!!!!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.