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anonymous

  • one year ago

math help question is in comment

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  1. anonymous
    • one year ago
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    In the equation x^2-13x+30=(x+g)(x+h) G and H are both intergers. There are two possible values for G. what are they im lost on how to do it

  2. anonymous
    • one year ago
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    you can use the master product rule. the key is to factor the equation. do yu know how to factor?

  3. anonymous
    • one year ago
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    yea

  4. anonymous
    • one year ago
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    so factor it and let's see what you get...

  5. anonymous
    • one year ago
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    (x−3)(x−10)

  6. anonymous
    • one year ago
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    so rewrtie your factors so that the operation between x and the integer is addition

  7. anonymous
    • one year ago
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    rewrite, sorry... do you understand?

  8. anonymous
    • one year ago
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    im lost

  9. anonymous
    • one year ago
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    so you have (x-3) and (x-10) as your factors, right?

  10. anonymous
    • one year ago
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    yea

  11. anonymous
    • one year ago
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    well, (x-3) = (x+[-3]), correct?

  12. anonymous
    • one year ago
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    no just (x-3)

  13. anonymous
    • one year ago
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    remember, subtraction is addition of the opposite. that's actually how subtraction is defined! what is the opposite of 3?

  14. anonymous
    • one year ago
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    -3

  15. anonymous
    • one year ago
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    there you go! so is 5-3 the same as 5+(-3)?

  16. anonymous
    • one year ago
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    but it says tht there are 2 possible factors for G

  17. anonymous
    • one year ago
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    (g+h)=-13 (g*h)=30

  18. anonymous
    • one year ago
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    yep... (x+(-3)) and (x+(-10))... does that make sense? a way to check is to see what values of x make the factors equal to 0. with (x-3), what value of x makes the factor 0? with (x +(-3)) what value of x makes the factor 0? is it the same value in both? if so, then the factors must be equivalent.

  19. anonymous
    • one year ago
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    so G can be either -3 or -10.

  20. anonymous
    • one year ago
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    ohhh i get it thx

  21. anonymous
    • one year ago
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    you're welcome

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