anonymous
  • anonymous
Can someone please help me with precalc? Can you just explain it to me please? In the lesson it said nothing about this, but I am sure it's easy, I just really don't understand. Please Help Use the graph below to show which numbered region belong to the graph of the solution set of each system of questions. http://assets.openstudy.com/updates/attachments/5405c9a6e4b0f2ed1e14d718-timaashorty-1409665469258-untitled.png Please explain, don't give me the answer! Thank you so much in advance!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
just a sec, i'll be right back to help
anonymous
  • anonymous
Ok, thank you so much!
anonymous
  • anonymous
first, identify the lines, ingnoring the inequality. line in #2, identify the line x =0 and the line y = x

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anonymous
  • anonymous
|dw:1441217653219:dw|
anonymous
  • anonymous
ok so its a vertical line? for x=0?
anonymous
  • anonymous
correct and it divides the plane into 2 regions... which region satisfies the inequality x>= 0?
anonymous
  • anonymous
hmm, if it was > or = to wouldn't that mean that it would be shaded on the right side?
anonymous
  • anonymous
|dw:1441217779384:dw|
anonymous
  • anonymous
correct! now we draw in the line y = x...
anonymous
  • anonymous
ok, http://www.regentsprep.org/regents/math/algebra/ac5/pracgraph1.gif
anonymous
  • anonymous
|dw:1441217904240:dw| which part satisfies the inequality y <= x?
anonymous
  • anonymous
hmm, I believe it would be on the right side of the line y=x? Since it is < or = to?
anonymous
  • anonymous
great!
anonymous
  • anonymous
|dw:1441218086190:dw| now which region satisfies both of the inequalities?
anonymous
  • anonymous
The section of it on the right side of the x-axis?
anonymous
  • anonymous
|dw:1441218200528:dw|
anonymous
  • anonymous
make sense?
anonymous
  • anonymous
Ok thank you, yes it does. So to answer that I would need to put it into a (x, y) form?
anonymous
  • anonymous
no, look at the question... it's asking what region or regions belong to the solution set. the regions are numbered so you must provide all of the numbers that relate to the proper region(s). what number(s) are valid?
anonymous
  • anonymous
any point within the region or regions must satisfy both inequalities.
anonymous
  • anonymous
Oh ok, sorry. So for that I would need to pick a plot and put it into the inequalities like an equation?
anonymous
  • anonymous
no... look at your link! see the numbers on the graph? what shape does number 5 pertain to?
anonymous
  • anonymous
ok, looking. So all of the numbers would have to satisfy both and the ones pictured in the original graph?
anonymous
  • anonymous
|dw:1441218845167:dw|oops, this is the region represented by 5
anonymous
  • anonymous
Ok so it would be all the points inside that section that would represent the region(s)?
anonymous
  • anonymous
yes. is region 5 in the solution set?
anonymous
  • anonymous
No, I am not sure. Would it have to be something like x=5 or in that format? Or would I just simply list region 5? Sorry trying to make sure I understand the whole process.
anonymous
  • anonymous
region 5 represents an infinity of points... you are only supposed to list the numbers of the regions, separated by commas. you need to read and understand the question before you can hope to answer it with any confidence and understanding. the region number is a simple way of identifying all the points within that region. just like California identifies all the points on the globe that are within the region defined as California.
anonymous
  • anonymous
So it would simply be 5? Since it is talking about regions and everything within 5 as you were saying would satisfy the inequalities. I apologize, this is a fairly easy concept I am sure, I just am relatively turned around.
anonymous
  • anonymous
you have to list ALL regions that satisfy the inequalities, separated by a comma. is 5 the ONLY region that satisfies the inequality? if so, then just put 5. If not, then you will have to put 5 and thena comma and then the next number and so on... good luck!
anonymous
  • anonymous
Ok, thank you so much! Medaled and fanned!

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