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nuccioreggie

  • one year ago

There are (32)4 ⋅ 30 bacteria in a petri dish. What is the total number of bacteria in the dish? 38 39 311 324

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  1. nuccioreggie
    • one year ago
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    @DanJS

  2. nuccioreggie
    • one year ago
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    @Michele_Laino

  3. Nnesha
    • one year ago
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    use ^ for exponents like 2 to the 3rd power would be 2^3

  4. Nnesha
    • one year ago
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    \[\huge\rm (3^2)^4 \times 3^0\] like this ?

  5. nuccioreggie
    • one year ago
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    6561

  6. Nnesha
    • one year ago
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    anything to the zero power equal to one \[\huge\rm x^0 =1~~~~(Anything)^0=1\]

  7. Nnesha
    • one year ago
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    don't use calculator !

  8. Nnesha
    • one year ago
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    exponent rule \[\huge\rm (x^m)^n = x^{m \times n}\] just multiply the exponents base would stay the same

  9. nuccioreggie
    • one year ago
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    I GOT IT ITS a THANKS

  10. DanJS
    • one year ago
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    sorry, just saw this ... i can't tell what the question actually is in order to get one of those answers

  11. Nnesha
    • one year ago
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    your answer choices are 3^8 3^9 3^(11) 3^(24)

  12. nuccioreggie
    • one year ago
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    its A BUT CAN U HELP ME WITH THIS ONE

  13. DanJS
    • one year ago
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    oh, haha, right on sorry

  14. nuccioreggie
    • one year ago
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    What is the simplified expression for 2 power 2 multiplied by 2 power 3 over 2 power 4? 20 21 22 23

  15. DanJS
    • one year ago
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    i tried all power combinations for the expression, but not the answers...

  16. DanJS
    • one year ago
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    \[\huge\frac{ 2^2 * 2^3 }{ 2^4 }\]

  17. DanJS
    • one year ago
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    since they all have the same base 2, and multiplied, you can combine that into a single term 2^ (power)

  18. DanJS
    • one year ago
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    have to memorize and practice a little the like 4 general power rules...

  19. nuccioreggie
    • one year ago
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    SO ITS C?

  20. DanJS
    • one year ago
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    http://www.rapidtables.com/math/number/exponent.htm scroll to the table, the first 5 riles is prolly good

  21. DanJS
    • one year ago
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    rules

  22. DanJS
    • one year ago
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    numerator, multiplying like bases, add the powers together

  23. DanJS
    • one year ago
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    2^5 / 2 ^4

  24. DanJS
    • one year ago
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    to move the bottom to the top, change the sign on the exponent, then use the addition of powers again

  25. Nnesha
    • one year ago
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    \[\huge\rm x^m \times x^n=x^{m+n}\] when we multiply same bases we should `ADD` their exponents and when you divide them you should `subtract` ther exponents \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\]

  26. DanJS
    • one year ago
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    2^5 * 2^(-4)

  27. DanJS
    • one year ago
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    = 2 or 2^1

  28. DanJS
    • one year ago
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    haha, you have those latex things saved for all the basic things?

  29. nuccioreggie
    • one year ago
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    it B

  30. nuccioreggie
    • one year ago
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    A closed container has 3.06 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10–24 grams. Which of the following shows and explains the approximate total mass, in grams, of all the atoms of the gas in the container? 0.47 grams, because (3.06 + 1.67) ⋅ (1023 ⋅ 10–24) = 4.73 ⋅ 10–1 0.51 grams, because (3.06 ⋅ 1.67) ⋅(1023 ⋅ 10–24) = 5.1102 ⋅ 10–1 4.73 grams, because (3.06 + 1.67) ⋅ (1023 ⋅ 10–24) = 4.73 5.11 grams, because (3.06 ⋅ 1.67) ⋅ (1023 ⋅ 10–24) = 5.1102

  31. DanJS
    • one year ago
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    ok, you good on those rules now

  32. nuccioreggie
    • one year ago
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    i just need help with couple more lol

  33. nuccioreggie
    • one year ago
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    A closed container has 3.06 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10–24 grams. Which of the following shows and explains the approximate total mass, in grams, of all the atoms of the gas in the container? 0.47 grams, because (3.06 + 1.67) ⋅ (1023 ⋅ 10–24) = 4.73 ⋅ 10–1 0.51 grams, because (3.06 ⋅ 1.67) ⋅(1023 ⋅ 10–24) = 5.1102 ⋅ 10–1 4.73 grams, because (3.06 + 1.67) ⋅ (1023 ⋅ 10–24) = 4.73 5.11 grams, because (3.06 ⋅ 1.67) ⋅ (1023 ⋅ 10–24) = 5.1102

  34. DanJS
    • one year ago
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    i-c

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