There are (32)4 ⋅ 30 bacteria in a petri dish. What is the total number of bacteria in the dish?
38
39
311
324

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- nuccioreggie

- chestercat

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- nuccioreggie

- nuccioreggie

- Nnesha

use ^ for exponents
like 2 to the 3rd power would be 2^3

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## More answers

- Nnesha

\[\huge\rm (3^2)^4 \times 3^0\] like this ?

- nuccioreggie

6561

- Nnesha

anything to the zero power equal to one \[\huge\rm x^0 =1~~~~(Anything)^0=1\]

- Nnesha

don't use calculator !

- Nnesha

exponent rule \[\huge\rm (x^m)^n = x^{m \times n}\] just multiply the exponents
base would stay the same

- nuccioreggie

I GOT IT ITS a THANKS

- DanJS

sorry, just saw this ... i can't tell what the question actually is in order to get one of those answers

- Nnesha

your answer choices are
3^8
3^9
3^(11)
3^(24)

- nuccioreggie

its A BUT CAN U HELP ME WITH THIS ONE

- DanJS

oh, haha, right on sorry

- nuccioreggie

What is the simplified expression for 2 power 2 multiplied by 2 power 3 over 2 power 4?
20
21
22
23

- DanJS

i tried all power combinations for the expression, but not the answers...

- DanJS

\[\huge\frac{ 2^2 * 2^3 }{ 2^4 }\]

- DanJS

since they all have the same base 2, and multiplied, you can combine that into a single term 2^ (power)

- DanJS

have to memorize and practice a little the like 4 general power rules...

- nuccioreggie

SO ITS C?

- DanJS

http://www.rapidtables.com/math/number/exponent.htm
scroll to the table, the first 5 riles is prolly good

- DanJS

rules

- DanJS

numerator, multiplying like bases, add the powers together

- DanJS

2^5 / 2 ^4

- DanJS

to move the bottom to the top, change the sign on the exponent, then use the addition of powers again

- Nnesha

\[\huge\rm x^m \times x^n=x^{m+n}\] when we multiply same bases we should `ADD` their exponents
and when you divide them you should `subtract` ther exponents \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\]

- DanJS

2^5 * 2^(-4)

- DanJS

= 2 or 2^1

- DanJS

haha, you have those latex things saved for all the basic things?

- nuccioreggie

it B

- nuccioreggie

A closed container has 3.06 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10–24 grams. Which of the following shows and explains the approximate total mass, in grams, of all the atoms of the gas in the container?
0.47 grams, because (3.06 + 1.67) ⋅ (1023 ⋅ 10–24) = 4.73 ⋅ 10–1
0.51 grams, because (3.06 ⋅ 1.67) ⋅(1023 ⋅ 10–24) = 5.1102 ⋅ 10–1
4.73 grams, because (3.06 + 1.67) ⋅ (1023 ⋅ 10–24) = 4.73
5.11 grams, because (3.06 ⋅ 1.67) ⋅ (1023 ⋅ 10–24) = 5.1102

- DanJS

ok, you good on those rules now

- nuccioreggie

i just need help with couple more lol

- nuccioreggie

- DanJS

i-c

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