## anonymous one year ago Medal and explain as well please. :) ♥ Question: A parabola has intercepts of x = -2, x = 3, and y = -4. Answer these a. Write the intercept form of the parabola. b. State the direction of the parabola. Explain. c. Write in ax2 + bx + c form. d. What is the axis of symmetry? e. What is the vertex? f. Graph the parabola. Label axis, vertex, and intercepts.

1. anonymous

2. Nnesha

what is the intercept form ? ax^2+bx+c = standard form y=a(x-h)^2+k vertex form

3. anonymous

thank you @Nnesha :D

4. Nnesha

x=-2 , x=3 set it equal to zero

5. anonymous

okay... then do I plug in something?

6. Nnesha

then you would apply foil method to get the standard form

7. anonymous

foil method? o.o//

8. Nnesha

(a+b)(c+d) multiply ? FOIL familiar with it ?

9. anonymous

-2^2 +3+-4=

10. anonymous

??? cross multiply, sorry I don't really remember...

11. anonymous

...

12. anonymous

y=(x^2+x^3)^4 ???

13. Nnesha

this is the intercept form of parabola $\huge\rm y=a(x-p)(x-q)$ where p and q are the x-intercepts y= y-intercept

14. Nnesha

a)^^

15. Nnesha

given x-intercepts are -2 and 3 so substitute p and q for -2 and 3

16. Nnesha

$\huge\rm y=a(x-(-2))(x-3)$ y intercept is (0 , -4) { y-intercept is a point where graph of the equation intersect y-axis when x=0 ) so substitute y for -4 and 0 for x solve for a

17. anonymous

I never really learned this, so don't be mad... Anyways okay

18. Nnesha

i've never heard abt intercept form this is first time i'm doing this

19. Nnesha

feel free to ask question if you don't get anything :)

20. Nnesha

http://www.virtualnerd.com/algebra-2/quadratics/transforming-functions/intercept-form/intercept-form-from-graph i watched this video watch this maybe you will understand like i said today is the first time i'm solving intercept form already familiar with vertex , standard form but not the intercept :D

21. anonymous

a= - y/2x(x-3)

22. anonymous

a=−y2x(x−3)

23. anonymous

okay :/

24. anonymous

25. Nnesha

replace y with -4

26. Nnesha

read the statement of the original question

27. anonymous

a=-4/2x(x-3)

28. Nnesha

$-4=a(x-(-2))(x-3)$ when y =-4 x would be 0 bec when line intersect at y-axis x=0 so replace x with 0

29. Nnesha

$\huge\rm -4=a(\color{reD}{0}-(-2))(\color{reD}{0}-3)$ like this now solve for a

30. anonymous

a=2/3

31. Nnesha

yes right so intercept for would be ? $\huge\rm y=a(x-p)(x-q)$ replace a with 2/3 p =-2 q=-3

32. anonymous

y= 1/2 (x --2) (x--3)?

33. Nnesha

a =2/3 not 1/2

34. anonymous

opps xD i don't know where that came from xD

35. Nnesha

$\huge\rm y=\frac{ 2 }{ 3 }(x\color{reD}{-(-2)})(x-3)$ distribute -(-2)

36. anonymous

y=2/3(x--2)(x--3)

37. Nnesha

hmm q isn't -3

38. Nnesha

$\huge\rm y=\frac{ 2 }{ 3 }(x\color{reD}{-(-2)})(x-(+3))$ distribute -(-2)

39. Nnesha

-1 times -2 = ? - times +3 = ?

40. anonymous

-2? 3

41. Nnesha

after that you wll with part a

42. Nnesha

negative times negative = positive

43. Nnesha

so -1 times -2 = ?

44. anonymous

2

45. Nnesha

yes so -1 times 3 = ?

46. anonymous

-3?

47. Nnesha

right

48. anonymous

okay xD

49. anonymous

2, -3

50. Nnesha

$\huge\rm y=\frac{ 2 }{ 3 }(x+2))(x-3)$

51. anonymous

y=2/3(x+2)(x-3)

52. anonymous

lol

53. Nnesha

yep!

54. anonymous

xD ♥

55. Nnesha

now multiply 2/3(x+2)(x-3) and i've to go now sorry its urgent :(

56. Nnesha

for part b) if a is positive then you will getu shape and if a is negative then you will hve n shape

57. Nnesha

cya

58. anonymous

sorry I had to go the restroom...

59. Nnesha

are you there ?

60. Nnesha

tag me when u're ready okay :)

61. anonymous

hey

62. anonymous

still here sups, aha

63. Nnesha

64. Nnesha

Write in ax2 + bx + c form.  multiply 2/2(x-3)(x+2)

65. anonymous

okay hold up

66. anonymous

x^2-x-6?

67. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @Nnesha Write in ax2 + bx + c form.  multiply 2/2(x-3)(x+2) $$\color{blue}{\text{End of Quote}}$$ 2/3**

68. Nnesha

(x+2)(x-3)=x^2-x-6 now multiply it by 2/3

69. anonymous

okay

70. Nnesha

let me know what u get

71. anonymous

I get nothing :/

72. Nnesha

what do you mean ?

73. anonymous

I get 0

74. anonymous

also sorry I had to leave the computer :/

75. Nnesha

how did you get 0 ?? 2/3(x-3)(x+2) ??

76. anonymous

multiplied....

77. anonymous

2x^2/3 - 2x/3 -4???