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anonymous

  • one year ago

Medal and explain as well please. :) ♥ Question: A parabola has intercepts of x = -2, x = 3, and y = -4. Answer these a. Write the intercept form of the parabola. b. State the direction of the parabola. Explain. c. Write in ax2 + bx + c form. d. What is the axis of symmetry? e. What is the vertex? f. Graph the parabola. Label axis, vertex, and intercepts.

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  1. anonymous
    • one year ago
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    @Nnesha please help?

  2. Nnesha
    • one year ago
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    what is the intercept form ? ax^2+bx+c = standard form y=a(x-h)^2+k vertex form

  3. anonymous
    • one year ago
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    thank you @Nnesha :D

  4. Nnesha
    • one year ago
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    x=-2 , x=3 set it equal to zero

  5. anonymous
    • one year ago
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    okay... then do I plug in something?

  6. Nnesha
    • one year ago
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    then you would apply foil method to get the standard form

  7. anonymous
    • one year ago
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    foil method? o.o//

  8. Nnesha
    • one year ago
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    (a+b)(c+d) multiply ? FOIL familiar with it ?

  9. anonymous
    • one year ago
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    -2^2 +3+-4=

  10. anonymous
    • one year ago
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    ??? cross multiply, sorry I don't really remember...

  11. anonymous
    • one year ago
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    ...

  12. anonymous
    • one year ago
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    y=(x^2+x^3)^4 ???

  13. Nnesha
    • one year ago
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    this is the intercept form of parabola \[\huge\rm y=a(x-p)(x-q)\] where p and q are the x-intercepts y= y-intercept

  14. Nnesha
    • one year ago
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    a)^^

  15. Nnesha
    • one year ago
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    given x-intercepts are -2 and 3 so substitute p and q for -2 and 3

  16. Nnesha
    • one year ago
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    \[\huge\rm y=a(x-(-2))(x-3)\] y intercept is (0 , -4) { y-intercept is a point where graph of the equation intersect y-axis when x=0 ) so substitute y for -4 and 0 for x solve for a

  17. anonymous
    • one year ago
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    I never really learned this, so don't be mad... Anyways okay

  18. Nnesha
    • one year ago
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    i've never heard abt intercept form this is first time i'm doing this

  19. Nnesha
    • one year ago
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    feel free to ask question if you don't get anything :)

  20. Nnesha
    • one year ago
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    http://www.virtualnerd.com/algebra-2/quadratics/transforming-functions/intercept-form/intercept-form-from-graph i watched this video watch this maybe you will understand like i said today is the first time i'm solving intercept form already familiar with vertex , standard form but not the intercept :D

  21. anonymous
    • one year ago
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    a= - y/2x(x-3)

  22. anonymous
    • one year ago
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    a=−y2x(x−3)

  23. anonymous
    • one year ago
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    okay :/

  24. anonymous
    • one year ago
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    @Robert136 please help?

  25. Nnesha
    • one year ago
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    replace y with -4

  26. Nnesha
    • one year ago
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    read the statement of the original question

  27. anonymous
    • one year ago
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    a=-4/2x(x-3)

  28. Nnesha
    • one year ago
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    \[-4=a(x-(-2))(x-3)\] when y =-4 x would be 0 bec when line intersect at y-axis x=0 so replace x with 0

  29. Nnesha
    • one year ago
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    \[\huge\rm -4=a(\color{reD}{0}-(-2))(\color{reD}{0}-3)\] like this now solve for a

  30. anonymous
    • one year ago
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    a=2/3

  31. Nnesha
    • one year ago
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    yes right so intercept for would be ? \[\huge\rm y=a(x-p)(x-q)\] replace a with 2/3 p =-2 q=-3

  32. anonymous
    • one year ago
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    y= 1/2 (x --2) (x--3)?

  33. Nnesha
    • one year ago
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    a =2/3 not 1/2

  34. anonymous
    • one year ago
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    opps xD i don't know where that came from xD

  35. Nnesha
    • one year ago
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    \[\huge\rm y=\frac{ 2 }{ 3 }(x\color{reD}{-(-2)})(x-3)\] distribute -(-2)

  36. anonymous
    • one year ago
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    y=2/3(x--2)(x--3)

  37. Nnesha
    • one year ago
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    hmm q isn't -3

  38. Nnesha
    • one year ago
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    \[\huge\rm y=\frac{ 2 }{ 3 }(x\color{reD}{-(-2)})(x-(+3))\] distribute -(-2)

  39. Nnesha
    • one year ago
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    -1 times -2 = ? - times +3 = ?

  40. anonymous
    • one year ago
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    -2? 3

  41. Nnesha
    • one year ago
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    after that you wll with part a

  42. Nnesha
    • one year ago
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    negative times negative = positive

  43. Nnesha
    • one year ago
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    so -1 times -2 = ?

  44. anonymous
    • one year ago
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    2

  45. Nnesha
    • one year ago
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    yes so -1 times 3 = ?

  46. anonymous
    • one year ago
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    -3?

  47. Nnesha
    • one year ago
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    right

  48. anonymous
    • one year ago
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    okay xD

  49. anonymous
    • one year ago
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    2, -3

  50. Nnesha
    • one year ago
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    \[\huge\rm y=\frac{ 2 }{ 3 }(x+2))(x-3)\]

  51. anonymous
    • one year ago
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    y=2/3(x+2)(x-3)

  52. anonymous
    • one year ago
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    lol

  53. Nnesha
    • one year ago
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    yep!

  54. anonymous
    • one year ago
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    xD ♥

  55. Nnesha
    • one year ago
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    now multiply 2/3(x+2)(x-3) and i've to go now sorry its urgent :(

  56. Nnesha
    • one year ago
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    for part b) if a is positive then you will get`u` shape and if a is negative then you will hve `n` shape

  57. Nnesha
    • one year ago
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    cya

  58. anonymous
    • one year ago
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    sorry I had to go the restroom...

  59. Nnesha
    • one year ago
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    are you there ?

  60. Nnesha
    • one year ago
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    tag me when u're ready okay :)

  61. anonymous
    • one year ago
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    hey

  62. anonymous
    • one year ago
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    still here sups, aha

  63. Nnesha
    • one year ago
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    okay great ready !?

  64. Nnesha
    • one year ago
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    `Write in ax2 + bx + c form. ` multiply 2/2(x-3)(x+2)

  65. anonymous
    • one year ago
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    okay hold up

  66. anonymous
    • one year ago
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    x^2-x-6?

  67. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Nnesha `Write in ax2 + bx + c form. ` multiply 2/2(x-3)(x+2) \(\color{blue}{\text{End of Quote}}\) 2/3**

  68. Nnesha
    • one year ago
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    (x+2)(x-3)=x^2-x-6 now multiply it by 2/3

  69. anonymous
    • one year ago
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    okay

  70. Nnesha
    • one year ago
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    let me know what u get

  71. anonymous
    • one year ago
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    I get nothing :/

  72. Nnesha
    • one year ago
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    what do you mean ?

  73. anonymous
    • one year ago
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    I get 0

  74. anonymous
    • one year ago
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    also sorry I had to leave the computer :/

  75. Nnesha
    • one year ago
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    how did you get 0 ?? 2/3(x-3)(x+2) ??

  76. anonymous
    • one year ago
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    multiplied....

  77. anonymous
    • one year ago
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    2x^2/3 - 2x/3 -4???

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