anonymous
  • anonymous
In which expression should the exponents be multiplied? one fifth to the 2nd times one fifth to the 6th 9 to the 3rd over 9 to the 4th 73 ⋅ 78 (26)−5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@phi
anonymous
  • anonymous
after this there is 2 more
phi
  • phi
you shout use ^ or the equation editor. I can't tell which numbers are exponents.

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anonymous
  • anonymous
oh let me fix it
phi
  • phi
but we did this in your first question \[ \left(7^3\right)^2 = 7^6\] notice that 2*3= 6 (that is the short cut)
anonymous
  • anonymous
1/5^2 x 1/5^6 9^3/9^4 7^3 x 7^8 (2^6)^-5
anonymous
  • anonymous
do u want a screenshot ?
phi
  • phi
no. it's clear. can you pick out the answer?
anonymous
  • anonymous
ok
anonymous
  • anonymous
let me see
anonymous
  • anonymous
(2^6)^-5??
phi
  • phi
yes. the answer is 2^(-30) the way to get that the long way is "flip" and make -5 +5 \[ \left(2^6\right)^{-5}= \frac{1}{\left(2^6\right)^{5}}= \frac{1}{2^6\cdot 2^6 \cdot 2^6\cdot 2^6\cdot 2^6}\]
anonymous
  • anonymous
ok
phi
  • phi
2^6 is 2*2*2*2*2*2 and there are 5 of those, which adds up to 2 times itself 30 times.
anonymous
  • anonymous
so when its multiplied up its 2^-(30) because 6x5 is 30
anonymous
  • anonymous
oh
anonymous
  • anonymous
ok ya
phi
  • phi
if you learn to do it the "hard way" it should make sense. and the short cuts will be easier to understand.
anonymous
  • anonymous
lol ok
anonymous
  • anonymous
alrighty thanks for the awesome help again i got 2 left

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