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anonymous

  • one year ago

In which expression should the exponents be multiplied? one fifth to the 2nd times one fifth to the 6th 9 to the 3rd over 9 to the 4th 73 ⋅ 78 (26)−5

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  1. anonymous
    • one year ago
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    @phi

  2. anonymous
    • one year ago
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    after this there is 2 more

  3. phi
    • one year ago
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    you shout use ^ or the equation editor. I can't tell which numbers are exponents.

  4. anonymous
    • one year ago
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    oh let me fix it

  5. phi
    • one year ago
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    but we did this in your first question \[ \left(7^3\right)^2 = 7^6\] notice that 2*3= 6 (that is the short cut)

  6. anonymous
    • one year ago
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    1/5^2 x 1/5^6 9^3/9^4 7^3 x 7^8 (2^6)^-5

  7. anonymous
    • one year ago
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    do u want a screenshot ?

  8. phi
    • one year ago
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    no. it's clear. can you pick out the answer?

  9. anonymous
    • one year ago
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    ok

  10. anonymous
    • one year ago
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    let me see

  11. anonymous
    • one year ago
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    (2^6)^-5??

  12. phi
    • one year ago
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    yes. the answer is 2^(-30) the way to get that the long way is "flip" and make -5 +5 \[ \left(2^6\right)^{-5}= \frac{1}{\left(2^6\right)^{5}}= \frac{1}{2^6\cdot 2^6 \cdot 2^6\cdot 2^6\cdot 2^6}\]

  13. anonymous
    • one year ago
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    ok

  14. phi
    • one year ago
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    2^6 is 2*2*2*2*2*2 and there are 5 of those, which adds up to 2 times itself 30 times.

  15. anonymous
    • one year ago
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    so when its multiplied up its 2^-(30) because 6x5 is 30

  16. anonymous
    • one year ago
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    oh

  17. anonymous
    • one year ago
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    ok ya

  18. phi
    • one year ago
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    if you learn to do it the "hard way" it should make sense. and the short cuts will be easier to understand.

  19. anonymous
    • one year ago
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    lol ok

  20. anonymous
    • one year ago
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    alrighty thanks for the awesome help again i got 2 left

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