## anonymous one year ago In which expression should the exponents be multiplied? one fifth to the 2nd times one fifth to the 6th 9 to the 3rd over 9 to the 4th 73 ⋅ 78 (26)−5

1. anonymous

@phi

2. anonymous

after this there is 2 more

3. phi

you shout use ^ or the equation editor. I can't tell which numbers are exponents.

4. anonymous

oh let me fix it

5. phi

but we did this in your first question $\left(7^3\right)^2 = 7^6$ notice that 2*3= 6 (that is the short cut)

6. anonymous

1/5^2 x 1/5^6 9^3/9^4 7^3 x 7^8 (2^6)^-5

7. anonymous

do u want a screenshot ?

8. phi

no. it's clear. can you pick out the answer?

9. anonymous

ok

10. anonymous

let me see

11. anonymous

(2^6)^-5??

12. phi

yes. the answer is 2^(-30) the way to get that the long way is "flip" and make -5 +5 $\left(2^6\right)^{-5}= \frac{1}{\left(2^6\right)^{5}}= \frac{1}{2^6\cdot 2^6 \cdot 2^6\cdot 2^6\cdot 2^6}$

13. anonymous

ok

14. phi

2^6 is 2*2*2*2*2*2 and there are 5 of those, which adds up to 2 times itself 30 times.

15. anonymous

so when its multiplied up its 2^-(30) because 6x5 is 30

16. anonymous

oh

17. anonymous

ok ya

18. phi

if you learn to do it the "hard way" it should make sense. and the short cuts will be easier to understand.

19. anonymous

lol ok

20. anonymous

alrighty thanks for the awesome help again i got 2 left