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x3_drummerchick
 one year ago
can someone explain to me how my teacher got this answer? its using substitution. Will give medals! give me one sec to post the problem
x3_drummerchick
 one year ago
can someone explain to me how my teacher got this answer? its using substitution. Will give medals! give me one sec to post the problem

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x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0\[x^{1/2}+3x^{1/2}54x^{3/2}=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x}+\frac{ 3 }{ \sqrt{x} }\frac{ 54 }{ \left( \sqrt{x} \right)^3 }=0\] \[put~\sqrt{x}=t\] \[t+\frac{ 3 }{ t }\frac{ 54 }{ t^3 }=0\] \[multiply~ by ~t^3\] \[t^4+3t^254=0\] put t^2=y \[y^2+3y54=0\] \[y^2+9y6y54=0\] y=? then t=? x=?

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0my teacher told us to try it like this: @surjithayer

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand the way he showed us in the above file

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yea i was abt to solve like ^^that (Factor )

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0where did the y come from?

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0our teacher wants us to factor it

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0i just dont get how he pulled out that exponential fraction

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2but i also like the way surjithayer's solved

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0i need to learn how to factor out the negative exponent :(

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2he supposed that t^2 = y

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2so t^4 is same as t^2 times t^2 replace t^2 with y y times y = y^2 :=)

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0i know how to use the substitution method, im just a little confused with how x^1/2 was fatored out.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2what's the lowest exponent of x ? that would be your common factor

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2wait i'll give you an example 2x^2+3x <x^1 degree would be common factor

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2so what is common factor in ur equation ?

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0x^3/2, ause its the smallest

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right!\[\huge\rm x^\frac{ 1 }{ 2 }+ 3x^\frac{ 1 }{ 2}+54x^\frac{ 3 }{ 2 }\] take out the common factor when you take out x^{3/2} from x^{1/2} what will ou have left ?\[x^\frac{ 3 }{ 2}(??????????????)\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2in other words divide all 3 terms by common factor \[\huge\rm \frac{ x^\frac{ 1 }{ 2 } }{ x^\frac{ 3 }{ 2 } }+\frac{ 3x^\frac{ 1 }{ 2 } }{ x^\frac{ 3 }{ 2 } }+\frac{ 54x^\frac{ 3 }{ 2 } }{ x^\frac{ 3 }{ 2 }}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2remember when we divide same bases we should `subtract `their exponents (exponent rule) \[ \huge\rm \frac{ x^m }{ x^n }=x^{mn}\]

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0^ thats ringing a bell

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2example \[\huge\rm \frac{ x^2 }{ x^1}=x^{21}\]

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0thats making such more sense

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \color{ReD}{ \frac{ x^\frac{ 1 }{ 2 } }{ x^\frac{ 3 }{ 2 } }}+\frac{ 3x^\frac{ 1 }{ 2 } }{ x^\frac{ 3 }{ 2 } }+\frac{ 54x^\frac{ 3 }{ 2 } }{ x^\frac{ 3 }{ 2 }}\] look at first term bases are the same so subtract their exponents \[\huge\rm \color{Red}{x^{\frac{ 1 }{ 2 }(\frac{ 3 }{ 2 })}}\]

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0i think i get it now, ou have to diivide all by it, that reduces it to the ax^2+bx+c

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0wow youre good, thanks!!!!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm x^\frac{ 3 }{ 2 }(????+???+??)\] write ur answer in the parentheses

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0ive got it from this point out. shew you have no idea how long ive been trying to decifer this shenninagans!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2aww se now you got it! great job!

x3_drummerchick
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much
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