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anonymous

  • one year ago

Identify square root of 2 as either rational or irrational, and approximate to the tenths place.

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  1. anonymous
    • one year ago
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    i got it

  2. zzr0ck3r
    • one year ago
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    The square root of a prime number is irrational. Go to wolframalpha.com and type sqrt{2} for an approximation

  3. anonymous
    • one year ago
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    irrational 1.4

  4. zzr0ck3r
    • one year ago
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    correct

  5. anonymous
    • one year ago
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    can i ask u another question?

  6. zzr0ck3r
    • one year ago
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    sure

  7. anonymous
    • one year ago
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    Solve x3 = 1 over 8. 1 over 2 ±1 over 2 1 over 4 ±1 over 4

  8. zzr0ck3r
    • one year ago
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    \(x^3=\dfrac{1}{8}\implies x=\sqrt[3]{\dfrac{1}{8}}\implies x=\dfrac{\sqrt[3]{1}}{\sqrt[3]{8}}\implies x=\dfrac{1}{\sqrt[3]{8}}= \ ?\)

  9. anonymous
    • one year ago
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    im confuzed

  10. zzr0ck3r
    • one year ago
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    Which step?

  11. anonymous
    • one year ago
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    2nd one

  12. zzr0ck3r
    • one year ago
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    1) I took the cube root of both sides which gives just \(x\) on the left and the cube root of the fraction on the right 2) the cube root of a fraction is the cube root of the numerator over the cube root of the denominator. 3) the cube root of \(1\) is \(1\). 4) what is the cube root of \(8\)?

  13. anonymous
    • one year ago
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    2.82

  14. anonymous
    • one year ago
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    is it C?

  15. zzr0ck3r
    • one year ago
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    what number times itself 3 times equals 8?

  16. anonymous
    • one year ago
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    2

  17. zzr0ck3r
    • one year ago
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    so \(x=\dfrac{1}{2}\)

  18. anonymous
    • one year ago
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    ok

  19. anonymous
    • one year ago
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    WaiT!!!!! @zzr0ck3r

  20. anonymous
    • one year ago
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    is it C or D im confussled

  21. anonymous
    • one year ago
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    i mean A OR B

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