anonymous
  • anonymous
Help with this parabola, 3x^2 +4x+12
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@Nnesha
campbell_st
  • campbell_st
well I can tell you its positive definite
Nnesha
  • Nnesha
statement ? factor ? solve for x ? graph ? write in vertex form? find vertex point ? what is axis sym ?

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anonymous
  • anonymous
I dont know how to find the zeros
Nnesha
  • Nnesha
alright zeros(solutions , x-intercept) you can use quadratic formula `OR` you can factor it
Nnesha
  • Nnesha
which one is easy for you ? factors or quadratic formula ?
anonymous
  • anonymous
Factors
Nnesha
  • Nnesha
ohh well nvm you have to apply the quadratic formula \[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
Nnesha
  • Nnesha
ax^2+bx+c quadratic equation where a=leading coefficient b=middle term c-constant term so what is a b and c in that equation ?
Nnesha
  • Nnesha
\(\huge\color{reD}{\rm b^2-4ac}\) `Discriminant` you can use this to find if the equation is factorable or not if ` b^2-4ac > 0` then there are 2 real zeros if ` b^2-4ac = 0` then there is one real root if ` b^2-4ac < 0` then you will get two complex roots (no -x-intercept)
Nnesha
  • Nnesha
zeros is another word they use for solutions and x-intercept
LynFran
  • LynFran
can u show me how to write it in vertex form .. @Nnesha
Nnesha
  • Nnesha
complete the square y=a(x-h)^2+k ?
LynFran
  • LynFran
o thats all lol... im now doing this ..thanks
Nnesha
  • Nnesha
i mean convert 3x^2 +4x+12 into y=a(x-h)^2+k <---(vertex form) b using completing the square method :=)
LynFran
  • LynFran
i know what u meant thanks
Nnesha
  • Nnesha
np :)
LynFran
  • LynFran
so it would be 3x^2+(4x/2)^2+......+12-..... (3x^2+4x+4)+12-4 (3x+2)^2+8 is this correct
LynFran
  • LynFran
i think i did something wrong
Nnesha
  • Nnesha
okay you need to complete the square of (3x^2+4x) it would be great if you take out the 3
Nnesha
  • Nnesha
i've to go rn cya later
LynFran
  • LynFran
ok

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