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anonymous
 one year ago
Find three consecutive odd integers whose sum is 72 more than the smallest integer.
anonymous
 one year ago
Find three consecutive odd integers whose sum is 72 more than the smallest integer.

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.2let smallest integer be x then x + x + 2 + x + 4 = x + 72

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0^^ and add 2 and 4 to both sides. That results in 3x=66+x Subtract x from each side, and you get 2x=66 Therefore, x=33!

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0Same thing we did last time, but use the smallest number on the right hand side of the equality.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so the smallest consecutive odd integer is X. but I'm still confused on the 2nd consecutive odd integer and the largest integer. Would the 2nd be x+2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. and the third integer would be (x+4).

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2the next odd number is 2 after the first Remember thers is an even number in between

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would be careful, @welshfella . Your expressions for the three integers does not require them to be odd. The solution will be odd only by luck. Generically, three consecutive odd integers are best represented by 2x+1, 2x+3, and 2x+5, where x is an integer. This GUARANTEES that the integers are odd.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you all so much! I understand it clearly now

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yes @ospreytriple  I took the chance. I'm lazy that's my problem!
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