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anonymous
 one year ago
Help with calculus!
anonymous
 one year ago
Help with calculus!

This Question is Closed

freckles
 one year ago
Best ResponseYou've already chosen the best response.2just take the terms with highest degree from top and bottom

freckles
 one year ago
Best ResponseYou've already chosen the best response.2like for 2x+1 the term with highest degree is 2x for x^22x+1 the term with highest degree is?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2right so your model for the first one is 2x/x^2 which can be reduced

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh so when they ask for power function end behavior model it's asking for the highest power?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And it would simplify to \[\frac{ 2 }{ x }\] right?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2yes and I guess you could name it... g(x)=2/x and you can find the horizontal asymptote from the model

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[\lim_{x \rightarrow \pm \infty } \frac{2}{x}=?\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.2here are more examples: http://chargermath.wikispaces.com/file/view/22+End+Behavior+Models.pdf

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wouldn't the horizontal asymptote be 0 when graphed?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2yep the horizontal asymptote would be y=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In number 1 from the link you sent, how did they get g(x)=4x^2? Did they just use the 4x^2 from the f(x)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. So for number 2 from my examples g(x)=2 and the horizontal asymptote equals.....2?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[f(x)=\frac{4x^25x+6}{1} \\ g(x)=\frac{4x^2}{1}=4x^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay that makes sense for the link problem 1.

freckles
 one year ago
Best ResponseYou've already chosen the best response.2yes g(x)=2 would be the model

freckles
 one year ago
Best ResponseYou've already chosen the best response.2and to find the horizontal aymsptote just evaluate: \[y=\lim_{x \rightarrow \pm \infty}2\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.2horizontal equations come in the form y=a number

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the actual answer would be y=2?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2just as the first one you asked about was y=0

freckles
 one year ago
Best ResponseYou've already chosen the best response.2by the way the one in the link doesn't have a horizontal asymptote

freckles
 one year ago
Best ResponseYou've already chosen the best response.2well the first one in that link I sent you

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How did they get 1 as the final answer for problem 1 in the link?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2they were just checking the right and left conditions

freckles
 one year ago
Best ResponseYou've already chosen the best response.2to see if it was a power function end behavior model

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So that step proves that using the power method is correct?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2yes as the pdf stated we need both \[\lim_{x \rightarrow \pm \infty}\frac{f(x)}{g(x)}=1 \]

freckles
 one year ago
Best ResponseYou've already chosen the best response.2this is to see f and g have the same kind of end behavior at both ends

freckles
 one year ago
Best ResponseYou've already chosen the best response.2and if that holds then yes it is end behavior model

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay thanks! Can you check these 2 questions as well? Just want to make sure I'm getting this right. I'll say the answer I got and just check it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.035.) g(x)=x^2; H.A.: y=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.036.) g(x)=x; H.A.: DNE or undetermined?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which part did I get wrong for 35?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2no ha as in no horizontal aymptote

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do you find the horizontal asymptote numerically? I don't think I'm understanding how to find it using the graphing method.

freckles
 one year ago
Best ResponseYou've already chosen the best response.2there is no polynomial that has a horizontal asymptote

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay. Was I right for the others?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2dw:1441235528085:dw but dw:1441235564894:dw do you see in the first graph the curve is approaching a line for really big values of x you can also see the graph is approaching a line for really big negative values of x that line being y=0 but nothing like that is happening in the second graph and yes you are right for the second question

freckles
 one year ago
Best ResponseYou've already chosen the best response.2I should add what kind of line I was talking about horizontal line

freckles
 one year ago
Best ResponseYou've already chosen the best response.2dw:1441235738250:dw see the curve getting closer to that dark horizontal line I drew that line being y=0

freckles
 one year ago
Best ResponseYou've already chosen the best response.2dw:1441235784454:dw

freckles
 one year ago
Best ResponseYou've already chosen the best response.2as we move out further and further from the origin in both left and right directions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay I got it. Thanks so much!

freckles
 one year ago
Best ResponseYou've already chosen the best response.2np so the only real correction you need to make 35 and 36 do not have horizontal asymptotes

freckles
 one year ago
Best ResponseYou've already chosen the best response.2g(x)=x^2 and g(x)=x for 35 and 36 respectively look great
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