A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

j2lie

  • one year ago

Does the function represented by the graph have an inverse function? The three coordinates are (0,0), (4,8), and (8,0).

  • This Question is Closed
  1. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Plot all of the points. If you can draw a horizontal straight line through any two points, then this function fails the horizontal line test. Any time you fail the horizontal line test, the function won't have an inverse.

  2. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I cannot, because the line is slanted on the graph.

  3. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    did you plot the three points?

  4. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes. It's been drawn for me.

  5. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ok is it possible to draw a flat horizontal line through more than one point?

  6. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes, between zero and eight.

  7. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yeah through (0,0) and (8,0) so this means the horizontal line test fails and we won't have an inverse function

  8. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Why? I think there should be an inverse. I just don't know the function for the graph.

  9. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    did you learn about the vertical line test?

  10. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Not yet. We're talking about functions and graphs. Also domain and range.

  11. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    well the rule about functions is that a relation must pass the vertical line test in order to be a function

  12. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    if you can pass a vertical line through more than one point, then the vertical line test fails and we do NOT have a function

  13. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok. But how do I find the function of the graph?

  14. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    In this case, we just have 3 points. It seems like there isn't enough information to find the actual function

  15. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    can you post a screenshot of the full thing?

  16. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I will check my notes, but they're confusing.

  17. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    I recommend watching this video about the vertical line test https://www.youtube.com/watch?v=-xvD-n4FOJQ hopefully it will help

  18. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I haven't learned that yet, so would it count if put the vertical and horizontal tests as my answer?

  19. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    if you haven't learned it, then the teacher probably won't accept it. But it's handy to learn nonetheless (chances are the teacher will teach it later down the road)

  20. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I need the exact answer, because I have a test tomorrow and I never got a question like this before. I can find the inverse of a function if it's given.

  21. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    can you post a screenshot of the full thing?

  22. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok. Sorry.

  23. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I cannot attach a picture.

  24. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the "attach file" button isn't working?

  25. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    maybe host it on a site like imgur and then paste the link

  26. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I have instagram.

  27. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    that might work, just as long as you can host the image somewhere and share the link

  28. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    My username is princess5062. You can see the picture that I just uploaded.

  29. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    https://instagram.com/p/7Ja6_CmGRgNTAiNKsvvsYhyWXzo4VLMRi9m1A0/?taken-by=princess5062

  30. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    it's telling me "Sorry, this page isn't available"

  31. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you have to have an account. It worked when I was logged on.

  32. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    oh sorry I don't have an account. There's no way to share to non-account holders?

  33. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    maybe I should i create an imgur account

  34. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you don't need to create one, they allow you to upload without an account

  35. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  36. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    thanks

  37. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Sorry, it took forever.

  38. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ok so it's a V shaped line, I see now

  39. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That's what I said like a parabola.

  40. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ok so the domain you have (0,8) is close but not quite there the actual domain is [0,8]. What's the difference? The difference is that the endpoints are included when you use square brackets.

  41. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh. It's because my friend said that the brackets are for the range only. Ok, thank you for that. Can I use any information I wrote down for the function?

  42. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    no, as long as there is a solid point on the graph, it is included. The endpoints have solid points (closed circles). if you saw open circles, then you would exclude those points

  43. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    `Can I use any information I wrote down for the function?` I'm not sure what you mean

  44. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Like the average rate of change, can I put that in an equation that is the function of the graph?

  45. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    oh, yes you can to describe the slope of each piece of the V shape

  46. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    so for #3, you'll have 2 answers there

  47. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That's the average rate of change also known as slope.

  48. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I got 2 and -2 for the rate of change. There is an inverse, because the signs are the opposite.

  49. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yes for the first half from 0 to 4, the slope is +2 the second half from 4 to 8 has the slope -2

  50. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Is it going to be an equation or inequality?

  51. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the graph you mean?

  52. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes, the function of the graph.

  53. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the function is an equation

  54. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I thought it was an equality, because 2 and -2 are opposite of each other.

  55. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so the equation is y=|x| + 2 = -2?

  56. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    equality is the same as equation both have "equa" in them an inequality is something like y > 2x which would involve shading

  57. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the vertex is at (4,8) so h = 4, k = 8 the value of 'a' is a = -2 because the V shape is stretched by a factor of 2. The negative is to mean "flip the V upside down" y = a|x-h|+k y = -2|x-4| + 8 is your equation

  58. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The function is not an equation with the letter y. We have to find the equation for the function.

  59. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you can replace y with f(x)

  60. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I might be wrong, because I looked at problem six, it's asking for an equation of the function.

  61. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yeah you start with y = |x| and do a bunch of transformations to end up with y = -2|x-4| + 8

  62. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Where did you get the eight?

  63. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    that's the y coordinate of the vertex

  64. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1441239501121:dw|

  65. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank you. How did you get the equation? Sorry, I'm not understanding your equation.

  66. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    I started with the template y = a|x-h|+k

  67. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    have you learned about y = a|x-h|+k ?

  68. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Did you multiply 2 and -2?

  69. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I haven't learned that yet.

  70. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I did, I'm so sorry. I am silly sometimes.

  71. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    so because the vertex is (4,8), this means h = 4 and k = 8. I plugged those in

  72. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    along with a = -2

  73. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so you moved -2 to both sides and multiplied 2 and -2?

  74. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    I got a = -2 from the fact that the slope of each piece of y = |x| is +1 and -1 but the slopes here are +2 and -2, so I doubled things to go from y = |x| to y = 2|x| then I flipped the V over to get y = -2|x|

  75. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok. Thank you for that clarification. So the function is -2|x-4|+8?

  76. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    y = -2|x-4|+8 or f(x) = -2|x-4|+8

  77. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f(x)=-2|x-4|+8

  78. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    here's the graph to check https://www.desmos.com/calculator/m8dav9jses

  79. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ignore the portions that aren't in quadrant 1

  80. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't know what to do on there

  81. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    it's basically a graphing calculator do you see the red V shape graph?

  82. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No. It's blank.

  83. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    hmm strange

  84. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you should see this

    1 Attachment
  85. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm sorry. I never used a graphing calculator before.

  86. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That's correct, but on my paper the number eight is not labeled.

  87. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    probably because it's cut off? not sure

  88. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Something like that. I need help finding the inverse of the function. The function is not in the regular form to create the inverse of a function.

  89. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    To find the inverse graphically, you take each point and swap the coordinates eg: (4,8) ---> (8,4) (8,0) ---> (0,8)

  90. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I need it in an equation.

  91. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    later on when you learn about the vertical line test, you'll find that the inverse is NOT a function

  92. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm sorry, but I'm doing it the way I learned.

  93. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    have you learned that absolute value functions are made up of two linear equations?

  94. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't know.

  95. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Do you mean like x=2 and x=-2?

  96. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    so the term "piecewise function" doesn't sound familiar?

  97. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No. sorry. I don't know what level math you're in right now.

  98. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    hmm I'm trying to figure out what the teacher wants and the method s/he wants you to use

  99. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    He wants me to use composition. Have you ever heard about that?

  100. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yes

  101. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok, I need help with making the function conforming to the composition rules.

  102. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't need the composition. I think, but it's to check the inverse function.

  103. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    I'm not sure how he wants you to find the inverse equation if you haven't learned about how an absolute value function is composed of 2 linear equations.

  104. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I know what you mean.

  105. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  106. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    all that shows how to find the inverse of a linear equation. So we just need to break up the V shape into 2 linear equations, then find the inverse of each piece

  107. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    How do I get that?

  108. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    focus on the left half of the V shape what two points are on this line?

  109. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (0,0) and (4,8)

  110. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    what is the equation of the line through those two points

  111. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't know. I know the slope.

  112. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    what's the slope

  113. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2

  114. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    what's the y intercept?

  115. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I think I'm going to be wrong, but is it (2,4)

  116. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    where does that line cross the y axis?

  117. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok. I'm feeling silly, but if the line continued wouldn't it be (0,0)

  118. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the left line goes through (0,0), yes

  119. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    slope = 2 ----> m = 2 y intercept = 0 ---> b = 0

  120. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the left piece of the line is y = 2x+0 or just y = 2x

  121. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The line would just 2x

  122. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1441241810907:dw|

  123. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So the line is 2x without 0?

  124. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    y=2x+0 is the same as y = 2x it's better to write the most simplified form to make things easier

  125. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok. I'm going to try and find the inverse.

  126. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The y intercept is a zero. It cannot have an inverse.

  127. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    why not?

  128. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you need to have an equation like y=x-4/3

  129. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It could work.

  130. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you can find the inverse of y = 2x though

  131. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    swap x and y, solve for y

  132. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I found it and I made the equation y=2x+0.

  133. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you should find the inverse to y = 2x is y = x/2

  134. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok, because the inverse cannot have zero?

  135. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    I don't know what you mean by not having 0

  136. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Never mind.

  137. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Should I use composition?

  138. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    I think composition is only used to verify you have the correct inverse (as your attached image shows)

  139. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'll use it. I need to make sure they are inverses.

  140. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ok so f(x) = 2x and g(x) = x/2 confirm that f( g(x) ) = x and g( f(x) ) = x

  141. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I got -2(x/2). Is that correct?

  142. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you should have 2(x/2) now simplify that

  143. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I got -x and -x for both compositions?

  144. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you should get +x

  145. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    2(x/2) = 2x/2 = x

  146. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but f(x)=-2x.

  147. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm sorry. I confused myself.

  148. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    no, f(x) = 2x

  149. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I wrote that when I tried it my way.

  150. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I fixed it and wrote x and x.

  151. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    so that confirms x/2 is the inverse of 2x

  152. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes. I understand that now

  153. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    now find the equation of the right half of the V

  154. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok.

  155. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    There is no y intercept for the right side. There is a x intercept.

  156. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    extend the line until it crosses the y axis

  157. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    or you can use y = mx+b and solve for b

  158. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    slope = -2 ---> m = -2 point on the line is (8,0) ---> x = 8 and y = 0

  159. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    y = mx+b y = -2x+b ... replace m with -2 0 = -2*8+b ... replace x with 8, replace y with 0 solve for b

  160. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why do you have to replace x with 8?

  161. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    because we know (8,0) is on that right half of the V

  162. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    we could use (4,8) as well

  163. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok. Now I will multiply -2 and 8.

  164. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    then isolate b

  165. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    to isolate b I will cross cancel b by adding -b.

  166. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    why not move the -16 over

  167. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f(x)=b-16

  168. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    0 = -2*8+b 0 = -16+b 16 = b ... Add 16 to both sides. so b = 16 agreed?

  169. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm starting to forget basic stuff, I'm sorry. I agree.

  170. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    slope = -2 m = -2 y-intercept = 16 b = 16

  171. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    y = mx+b turns into y = -2x+16

  172. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1441243656946:dw|

  173. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok. I got it. Now I need to find the inverse.

  174. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I got the answer. The answer is x and x.

  175. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    what inverse did you get

  176. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The inverse is x and x.

  177. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    those are the results after you do the composition

  178. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes.

  179. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    what is the actual inverse

  180. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't know. I'm sorry.

  181. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    did you solve x = -2y+16 for y?

  182. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes I did.

  183. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    and you got y = ??

  184. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I got x.

  185. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    forget about the composition stuff for now

  186. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    isolate y in `x = -2y+16`

  187. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm sorry I did not solve it, but if you mean y=x-16/-2

  188. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then I did solve it.

  189. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    good

  190. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you can also write that as y = (16-x)/2

  191. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes. I'm right. I got the composition correctly right?

  192. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yes if you ended up with x for each composition, you confirmed you have the correct inverse

  193. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes. Can you help with the rest of page? Or are you tired?

  194. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Me^

  195. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    how much is left?

  196. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    three problems and I have the answers I just need to make sure they're right.

  197. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ok I can check what you have

  198. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok. Please wait.

  199. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ok, I'll be right back.

  200. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok.

  201. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  202. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    for #5 they want you to describe how the parent function is changing

  203. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    how is y = |x| transformed into that V shape you see?

  204. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    by points?

  205. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you agree that the graph of y = |x| looks like this right? |dw:1441247206827:dw|

  206. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't agree. It's upside down.

  207. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    well the graph you have is upside down, but that isn't the graph of y = |x|

  208. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the two are similar though which is why we apply a bunch of transformations

  209. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Mine is not upside down. Mine is right, you're looking at it wrong.

  210. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    this is what |x| looks like http://demo.activemath.org/ActiveMath2/LeAM_calculusPics/AbsValue.png?lang=en

  211. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No it's not, it's going down.

  212. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the teacher is trying to get you to transform what I posted into what you have

  213. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    at some point, the graph will flip

  214. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no. It won't we haven't learned that yet.

  215. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    hmm let me think

  216. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    it's so strange how they want you to find the inverse when you haven't learned about horizontal/vertical line tests and how they ask about transformations when you haven't covered that either

  217. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You're taking harder Algebra.

  218. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yeah I'm thinking of a different algebra class maybe

  219. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm taking Algebra 2. How about you?

  220. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    your best bet is to ask the teacher since he'll know what he wants

  221. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    I'm not in algebra, but I'm probably thinking of another algebra class

  222. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So your other answers are wrong? There are only two algebra classes.

  223. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    No I'm quite sure the answers I got are correct. It's just sometimes the teacher wants you to do things a very specific way

  224. j2lie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Then I am going to cry.

  225. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.