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anonymous
 one year ago
Help with calculus!
anonymous
 one year ago
Help with calculus!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \lim }{ x \rightarrow7^{+} }f(x)=\infty \]Graph this.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3how far did you get?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3I'm going to start a blank xy graph. Add to the graph what you have so far dw:1441237470407:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3click the pencil on my drawing to be able to draw on it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I couldn't figure out where to start.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How can you draw infinity?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3ok let's start by plotting a point at 7 on the x axis dw:1441237530533:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3then draw a vertical dashed line through 7 dw:1441237577069:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3the limit says "as x gets closer and closer and closer to 7 from the right side, the value of y heads off to negative infinity" so there are a number of ways to do this. You could have something like this dw:1441237684271:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3or something like this dw:1441237697243:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3or maybe something like this dw:1441237713578:dw the majority of this graph doesn't matter as long as you approach infinity as you get closer to 7 from the right side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh..that makes much more sense. Can you check my answers for some others? I think I might have them wrong.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much!\[\frac{ \lim }{ x \rightarrow5^{+} }f(x)=8\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441237595205:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's what I put but I don't think it's right...

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3I'm going to delete the horizontal line dw:1441237965993:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3the idea here is that as we get closer to x = 5 from the right side, the y value gets closer to 8 so here is one way to do it dw:1441238039952:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3here is an alternative way dw:1441238056519:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So there is no line coming from the right?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3just like before, the majority of it doesn't matter as long as you end up at y = 8 when you approach from the right side of x = 5

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3`So there is no line coming from the right?` what do you mean?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3oh, that could be possible, yes you could have dw:1441238163678:dw or dw:1441238177135:dw and I'm just realizing that your example is perfectly valid. You can approach x = 5 from the right and end up getting closer and closer to y = 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So why do they need a plus next to the 5 under the limit?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3that notation means "right hand limit" since we're approaching from the right side of that x value

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So how does that apply to the graph?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3for right hand limits, you don't need to worry about the left side so that's why we could stop at x = 5 and not continue on

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3it allows us to graph more variety we could have graphs that stop at x = 5 or we could have graphs that continue on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay I'm going to go with your answer just in case.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \lim }{ x \rightarrow \infty }f(x)=4\]

Zarkon
 one year ago
Best ResponseYou've already chosen the best response.0a little \(\LaTeX\) help for you \[\lim_{ x \to\infty }f(x)=4\] \lim_{ x \to\infty }f(x)=4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441238256310:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3it's a tool to help write math notation

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3that graph you drew is correct here is another possible answer for the limit \[\Large \lim_{x\to\infty}f(x) = 4\] dw:1441238706491:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3and another possible answer dw:1441238735088:dw the idea is to get closer to that horizontal line as x gets larger

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3of course, we could cross that horizontal line like this dw:1441238767240:dw but notice how we still approach that horizontal line as x gets bigger

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so if the number under the limit is + or  that number, would I just extend the line like what I did on the second problem?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3I'm not sure what you mean

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3you mean like that \(\Large 5^{+}\) notation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ya the notation on the top. If it is + and  (left and right) would you extend the line across the graph like what I did in the 2nd problem I gave?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3It's possible to extend it through, but also just as valid to stop at that x value. Both interpretations are valid for that onesided limit If you were talking about a 2sided limit, then you would have to extend it through because you would be approaching that x value from both sides (left and right)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3dw:1441239084919:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3dw:1441239111134:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3dw:1441239138986:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay I understood that. Last one:\[\left(\begin{matrix}\lim \\ x \rightarrow\infty\end{matrix}\right)f(x)=2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441238954330:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry the drawing board was malfunctioning

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's suppose to be a straight line

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3one last thing though, it's possible to evaluate a onesided limit on a connected curve. Just approach from one side dw:1441239320678:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh ya! I forgot about that.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3as for your other problem, as long as you're approaching y = 2 as x heads off to negative infinity, then you have the proper graph another valid answer is this dw:1441239584767:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3something like this is also possible dw:1441239609022:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay thanks! That's all I needed. :)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3you're welcome
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