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anonymous

  • one year ago

In the middle of town, State and Elm streets meet at an angle of 40º. A triangular pocket park between the streets stretches 100 yards along State Street and 53.2 yards along Elm Street. What formula for the area of the pocket park would you use

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  1. anonymous
    • one year ago
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    A = 1/2(sin40º)(53.2 yd) A = 1/2 (sin100º)(53.2 yd) A = (100 yd)(sin50º)(53.2 yd) A = 1/2 (100 yd)(sin40º)(53.2 yd)

  2. DanJS
    • one year ago
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    draw it up, looks like you are given side - angle - side values

  3. DanJS
    • one year ago
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    |dw:1441237709949:dw|

  4. anonymous
    • one year ago
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    I think it's the last one.

  5. DanJS
    • one year ago
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    The area of a triangle is (1/2)*base*height

  6. DanJS
    • one year ago
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    maybe easier to orient it different.... |dw:1441237983462:dw|

  7. DanJS
    • one year ago
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    |dw:1441238059312:dw|

  8. anonymous
    • one year ago
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    So the last one then

  9. DanJS
    • one year ago
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    so the area of the red triangle is (1/2) * base * height = (1/2) * 100 * h

  10. DanJS
    • one year ago
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    since h is part of a right triangle, you can use trig function to rewrite its value

  11. DanJS
    • one year ago
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    you get what i did so far?, almost done

  12. anonymous
    • one year ago
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    Yeah kinda lol

  13. DanJS
    • one year ago
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    Since you already know the hypotenuse, you can use sin(40) to find h, sin(40) = opposite side / hypotenuse sin(40) = h / 53.2

  14. DanJS
    • one year ago
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    so h = 53.2 * sin(40)

  15. anonymous
    • one year ago
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    Omg so I was right. It's 1/2(100)(Sin40)(53.2)

  16. DanJS
    • one year ago
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    yeah, you guess or do that work? :)

  17. anonymous
    • one year ago
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    Did the work just wasn't sure. Mind helping me with one more? Then I'm done

  18. DanJS
    • one year ago
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    sure, start a new clean thread

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