The arc length of the circle is 100 degrees and is 7 meters. Find the perimeter of the sector.

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- anonymous

The arc length of the circle is 100 degrees and is 7 meters. Find the perimeter of the sector.

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- jdoe0001

hmmm the arc length is 100 degrees? as opposed to 100 meters?

- anonymous

I have no clue. i guess its safe to assume that cause all it says is the arc length is a 100 degrees. The length of that stretched out is 7 meters. So i have to find the perimeter of the sector which i dont even know what that is.

- jdoe0001

|dw:1441238511043:dw|

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## More answers

- anonymous

|dw:1441237812416:dw|

- anonymous

I thought that was the arc length

- anonymous

cause thats the central angle

- jdoe0001

right, but the arc's lenght is not given in degrees, it'd be a flat measuring unit, like meter, or feet
now, the central angle of the arc, would be 100 degrees

- anonymous

o

- jdoe0001

so..hmm it sounds a lot like |dw:1441238753083:dw| if that's the case, all you'd need to get is the arc's length
and sum it to the radii given

- anonymous

Yeah... i dont really know how to do that

- jdoe0001

\(\bf \textit{arc's length}=s=\cfrac{\theta\cdot \pi\cdot r }{180}\impliedby \theta\textit{ in degrees}\)

- jdoe0001

so the perimeter is
7 +
arc's length +
7

- anonymous

Am i suppose to get a decimal??

- jdoe0001

yes

- anonymous

can i put 16pi/3 for exact???? as the arc length??

- jdoe0001

well.. you could also keep as rational as well
got any choices on what's expected? float or rational?

- jdoe0001

sure

- anonymous

so 30.7552????

- jdoe0001

well... I get another figure
https://www.google.com/search?client=opera&q=7%2B(100*pi*7/180)%2B7&sourceid=opera&ie=utf-8&oe=utf-8&channel=suggest&gws_rd=ssl

- anonymous

hmmm

- anonymous

what would be the exact form

- jdoe0001

ohh .. one sec

- jdoe0001

\(\bf \cfrac{\theta\pi r}{180}\implies \cfrac{100\cdot \pi \cdot 7}{180}\implies \cfrac{35\pi }{9}
\\ \quad \\
7+\cfrac{35\pi }{9}+7\implies 14+\cfrac{35\pi }{9}\)

- anonymous

That would be the perimeter?

- jdoe0001

yes

- jdoe0001

we could use 3.1416 for \(\pi\) , then again, that'd make it a float, or decimal :)

- anonymous

yeah. Can u help me on one last question please??

- anonymous

Solve using S=r(theta)
Radius Central Angle Arc length
? pi/3 3/2 m

- jdoe0001

very straighforward
you said it ->S =r(theta)

- jdoe0001

\(\frac{\pi }{3}\) is already in radian units
so S = r * \(\theta\)

- anonymous

3/2 = r(pi/3)

- anonymous

- anonymous

- anonymous

everytime i solve it i get a weird decimal and its confusing me

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