anonymous
  • anonymous
formula to find the vertex of y=2(x+1)square-1
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Vertex for being y=a(x-h)^2 +k, you just need to plug in the numbers and do the math
anonymous
  • anonymous
I don't really get you question, are you trying to find the vertex?
anonymous
  • anonymous
normaly i m using -b over 2a to find the vertex, where should i use at here?

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anonymous
  • anonymous
it depends on what you are trying to find.
anonymous
  • anonymous
the vertex. I know y=(a)square+bx+c using -b over 2a to find the vertex, but how could i find the vertex at here?
anonymous
  • anonymous
well, the equation is already in vertex form, so just solve.
anonymous
  • anonymous
i don't get. I know the vertex is (-1,-1). But I need to show how i find the vertex
anonymous
  • anonymous
hang on, lemme put it in geo gebra
anonymous
  • anonymous
kk
anonymous
  • anonymous
that's it, the vertex is at( -1 -1) you had it. You just need to show how you get it?
anonymous
  • anonymous
yes, that is what i m asking
anonymous
  • anonymous
Well, how i did it is i put the equation into my graphing software and the lowest point of the graph is the vertex|dw:1441240202409:dw|
anonymous
  • anonymous
That help or no?
anonymous
  • anonymous
a little, i still need to ask my teacher tomorrow, but thank you:)
anonymous
  • anonymous
So all you have to do is graph the function and find the central point of the parabola, and that point is the vertex i believe.
anonymous
  • anonymous
you're welcome :)

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