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anonymous

  • one year ago

formula to find the vertex of y=2(x+1)square-1

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  1. anonymous
    • one year ago
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    Vertex for being y=a(x-h)^2 +k, you just need to plug in the numbers and do the math

  2. anonymous
    • one year ago
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    I don't really get you question, are you trying to find the vertex?

  3. anonymous
    • one year ago
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    normaly i m using -b over 2a to find the vertex, where should i use at here?

  4. anonymous
    • one year ago
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    it depends on what you are trying to find.

  5. anonymous
    • one year ago
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    the vertex. I know y=(a)square+bx+c using -b over 2a to find the vertex, but how could i find the vertex at here?

  6. anonymous
    • one year ago
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    well, the equation is already in vertex form, so just solve.

  7. anonymous
    • one year ago
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    i don't get. I know the vertex is (-1,-1). But I need to show how i find the vertex

  8. anonymous
    • one year ago
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    hang on, lemme put it in geo gebra

  9. anonymous
    • one year ago
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    kk

  10. anonymous
    • one year ago
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    that's it, the vertex is at( -1 -1) you had it. You just need to show how you get it?

  11. anonymous
    • one year ago
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    yes, that is what i m asking

  12. anonymous
    • one year ago
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    Well, how i did it is i put the equation into my graphing software and the lowest point of the graph is the vertex|dw:1441240202409:dw|

  13. anonymous
    • one year ago
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    That help or no?

  14. anonymous
    • one year ago
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    a little, i still need to ask my teacher tomorrow, but thank you:)

  15. anonymous
    • one year ago
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    So all you have to do is graph the function and find the central point of the parabola, and that point is the vertex i believe.

  16. anonymous
    • one year ago
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    you're welcome :)

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spraguer (Moderator)
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