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amy0799
 one year ago
if f(x) = (x^2c^2)/(x^2+c^2) where c is a constant, find f'(x)
amy0799
 one year ago
if f(x) = (x^2c^2)/(x^2+c^2) where c is a constant, find f'(x)

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x) = \frac {x^2c^2}{x^2+c^2}\] simplify? \[f(x) = \frac {x^2+c^22c^2}{x^2+c^2} = 1  \frac{2c^2}{x^2 + c^2}\] can you finish this?

amy0799
 one year ago
Best ResponseYou've already chosen the best response.1i thought it would be \[\frac{ 2x2c }{ 2x+2c }\]

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1why did you think that?

amy0799
 one year ago
Best ResponseYou've already chosen the best response.1hold on, i know what i did wrong

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1and remember, c is a constant so \(\frac{d}{dx} \left[ c^2 \right] = 0\)

amy0799
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ (x ^{2} +c ^{2})2x(x ^{2{}}c ^{2})2x}{ (x ^{2} +c ^{2})^{2}}\] is this right?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1you are applying the quotient rule. before i look at your work, is that what you are supposed to be doing with this because it is a silly way to do it. it just adds complications. let me know either way and we can proceed

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1your application of the quotient rule is correct

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1if you wish to do it this way, next step is to simplify the numerator

amy0799
 one year ago
Best ResponseYou've already chosen the best response.1simpliflying it would get me \[\frac{ 4xc ^{2} }{ (x ^{2}+c ^{2})^{2} }\]
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