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anonymous

  • one year ago

Solve using S=r(theta) Radius Central Angle Arc length ? pi/3 3/2 m

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  1. anonymous
    • one year ago
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    its 3/2=pi/3(r) i dont know how to find r

  2. anonymous
    • one year ago
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    @robtobey please please please help me

  3. anonymous
    • one year ago
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    i obviously know that i have to get r by itself but i dont know how cause the pi is confusing me.

  4. anonymous
    • one year ago
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    @jim_thompson5910

  5. anonymous
    • one year ago
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    @jim_thompson5910

  6. jim_thompson5910
    • one year ago
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    so you want to solve \[\Large \frac{3}{2} = \frac{\pi}{3}r\] for r?

  7. jim_thompson5910
    • one year ago
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    if so, multiply both sides by the reciprocal of pi/3 \[\Large \Large \frac{3}{2} = \frac{\pi}{3}r\] \[\Large \Large \color{red}{\frac{3}{\pi}}*\frac{3}{2} = \color{red}{\frac{3}{\pi}}*\frac{\pi}{3}r\]

  8. anonymous
    • one year ago
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    i just keep getting a decimal.

  9. anonymous
    • one year ago
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    oooooooooo..... 9/2pi

  10. jim_thompson5910
    • one year ago
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    yeah I'd leave it as a fraction and leave it in terms of pi

  11. anonymous
    • one year ago
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    \[\pi d=\text{circumfrence} \]\[\pi 2 r=\text{circumfrence} \]\[\frac{\pi 2 r}{6}=\frac{\text{circumfrence}}{6} \]\[\frac{\pi 2 r}{6}=\frac{3}{2} \]Solve for r.

  12. jim_thompson5910
    • one year ago
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    \[\Large r = \frac{9}{2\pi}\]

  13. anonymous
    • one year ago
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    That is what Mathematica calculated.

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