anonymous
  • anonymous
Solve using S=r(theta) Radius Central Angle Arc length ? pi/3 3/2 m
Mathematics
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anonymous
  • anonymous
Solve using S=r(theta) Radius Central Angle Arc length ? pi/3 3/2 m
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
its 3/2=pi/3(r) i dont know how to find r
anonymous
  • anonymous
@robtobey please please please help me
anonymous
  • anonymous
i obviously know that i have to get r by itself but i dont know how cause the pi is confusing me.

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anonymous
  • anonymous
anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
so you want to solve \[\Large \frac{3}{2} = \frac{\pi}{3}r\] for r?
jim_thompson5910
  • jim_thompson5910
if so, multiply both sides by the reciprocal of pi/3 \[\Large \Large \frac{3}{2} = \frac{\pi}{3}r\] \[\Large \Large \color{red}{\frac{3}{\pi}}*\frac{3}{2} = \color{red}{\frac{3}{\pi}}*\frac{\pi}{3}r\]
anonymous
  • anonymous
i just keep getting a decimal.
anonymous
  • anonymous
oooooooooo..... 9/2pi
jim_thompson5910
  • jim_thompson5910
yeah I'd leave it as a fraction and leave it in terms of pi
anonymous
  • anonymous
\[\pi d=\text{circumfrence} \]\[\pi 2 r=\text{circumfrence} \]\[\frac{\pi 2 r}{6}=\frac{\text{circumfrence}}{6} \]\[\frac{\pi 2 r}{6}=\frac{3}{2} \]Solve for r.
jim_thompson5910
  • jim_thompson5910
\[\Large r = \frac{9}{2\pi}\]
anonymous
  • anonymous
That is what Mathematica calculated.

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