A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Simplify 10 log 2003 without a calculator. Remember that 10 log (2) = 3dB.
Not sure which direction to go. I get 10log2003/log10 or 3dB + 10log(2003/2) when I try to use the hint.
anonymous
 one year ago
Simplify 10 log 2003 without a calculator. Remember that 10 log (2) = 3dB. Not sure which direction to go. I get 10log2003/log10 or 3dB + 10log(2003/2) when I try to use the hint.

This Question is Closed

kropot72
 one year ago
Best ResponseYou've already chosen the best response.210 log 2003 = 10(log2 + log 1003) The question is suggesting using the value of 0.3 for log 2, which rounds the actual value to 2 decimal places. Therefore we can use 3.0 for log 1000. Can you now find the answer?

kropot72
 one year ago
Best ResponseYou've already chosen the best response.210 log 2003 = 10(log 2 + log 1003) = 10(0.3 + 3.0) = ?

kropot72
 one year ago
Best ResponseYou've already chosen the best response.2@optiquest Are you there?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry was working another problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does 10(log2 + log 1003) = 10(log 2006) ?

kropot72
 one year ago
Best ResponseYou've already chosen the best response.2Yes you are correct. However if we write: 10(log 2003) = 10(log 2 + log 1001.5) the right hand side would still become 10(0.3 + 3.0) for the same reason i gave previously.

kropot72
 one year ago
Best ResponseYou've already chosen the best response.2@optiquest Are you cool with the answer now?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.