A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

You attach a block to the bottom end of a spring hanging vertically. You slowly let the block move down and find that it hangs at rest with the spring stretched by 15 cm. Next, you lift the block back up to the initial position and release it from rest with the spring un-stretched. What maximum distance does it move down?

  • This Question is Open
  1. IrishBoy123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    use the fist part to get a proxy for the spring constant, using F = kx = mg. so you know that here \(k = \frac{mg}{???}\) then for the second part, once released the block will next stop when the gravitiational potential energy it loses by moving down is converted entirely into spring energy. so if it drops by A, then you can say \(mgA = \frac{1}{2}kA^2\) and you know k from the first part

  2. Spring98
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hey I'm not hanging vertically am I?

  3. IrishBoy123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.