## anonymous one year ago You attach a block to the bottom end of a spring hanging vertically. You slowly let the block move down and find that it hangs at rest with the spring stretched by 15 cm. Next, you lift the block back up to the initial position and release it from rest with the spring un-stretched. What maximum distance does it move down?

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1. IrishBoy123

use the fist part to get a proxy for the spring constant, using F = kx = mg. so you know that here $$k = \frac{mg}{???}$$ then for the second part, once released the block will next stop when the gravitiational potential energy it loses by moving down is converted entirely into spring energy. so if it drops by A, then you can say $$mgA = \frac{1}{2}kA^2$$ and you know k from the first part

2. Spring98

hey I'm not hanging vertically am I?

3. IrishBoy123

yes