Find the standard form of the equation of the line.

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Find the standard form of the equation of the line.

Mathematics
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27) (2,5) (5,7)
is it as easy as the last one?
oh no it is not did you get the slope?

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Other answers:

Yes. The slope is 2/3.
I know I use this formula. Y=mx+b
ok then use the point slope formula pick a point
Okay. (2,5).
no dear we are not going to use that, we are going to so something else pick a point from the two you have
Oh. Okay!
ok now write \[y-y_1=m(x-x_1)\] with \[x_1=2,y_1=5,m=\frac{3}{2}\]
oops i meant \(m=\frac{2}{3}\)
you should be looking at \[y-5=\frac{2}{3}(x-2)\] right?
i already did that and got y=(2/3)x+(11/3)
now if you were going to write this in "point slope" form you would solve for \(y\) but you want "standard form" \[ax+by=c\]
Oh.
yeah but you went too far you got it in slope intercept form you were asked for standard form
lets start here \[y-5=\frac{2}{3}(x-2)\] it i easier
multiply both sides by \(3\) to get \[3y-15=2(x-2)\]
notice of course you have to multiply both sides by 3
then distribute \[3y-15=2x-4\]
put all the variables on one side, numbers on the other get \[3y-2x=11\] or \[2x-3y=-11\] that is "standard form"
You're right! Gosh, I thought I didn't take it far enough but I went way too far. Thank you again, Misty!
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