## anonymous one year ago Find the standard form of the equation of the line.

1. anonymous

27) (2,5) (5,7)

2. misty1212

is it as easy as the last one?

3. misty1212

oh no it is not did you get the slope?

4. anonymous

Yes. The slope is 2/3.

5. anonymous

I know I use this formula. Y=mx+b

6. misty1212

ok then use the point slope formula pick a point

7. anonymous

Okay. (2,5).

8. misty1212

no dear we are not going to use that, we are going to so something else pick a point from the two you have

9. anonymous

Oh. Okay!

10. misty1212

ok now write $y-y_1=m(x-x_1)$ with $x_1=2,y_1=5,m=\frac{3}{2}$

11. misty1212

oops i meant $$m=\frac{2}{3}$$

12. misty1212

you should be looking at $y-5=\frac{2}{3}(x-2)$ right?

13. anonymous

i already did that and got y=(2/3)x+(11/3)

14. misty1212

now if you were going to write this in "point slope" form you would solve for $$y$$ but you want "standard form" $ax+by=c$

15. anonymous

Oh.

16. misty1212

yeah but you went too far you got it in slope intercept form you were asked for standard form

17. misty1212

lets start here $y-5=\frac{2}{3}(x-2)$ it i easier

18. misty1212

multiply both sides by $$3$$ to get $3y-15=2(x-2)$

19. misty1212

notice of course you have to multiply both sides by 3

20. misty1212

then distribute $3y-15=2x-4$

21. misty1212

put all the variables on one side, numbers on the other get $3y-2x=11$ or $2x-3y=-11$ that is "standard form"

22. anonymous

You're right! Gosh, I thought I didn't take it far enough but I went way too far. Thank you again, Misty!

23. misty1212

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