anonymous
  • anonymous
square root of -5 multiplied by square root of 5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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j2lie
  • j2lie
-5 and 5 does not have a perfect square root.
anonymous
  • anonymous
\[\sqrt{-5} \times \sqrt{5}\]
anonymous
  • anonymous
So what does that mean?

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More answers

j2lie
  • j2lie
The square root is between 2 and 3.
anonymous
  • anonymous
I dont get it
j2lie
  • j2lie
the square root is either 2.5 or below.
kropot72
  • kropot72
\[\large \sqrt{-1}=i\] The square root of negative one is the imaginary number i. Factorising the square root of negative 5 we get: \[\large \sqrt{-5}\times \sqrt{5}=(\sqrt{5}\times \sqrt{5})i\]
kropot72
  • kropot72
The get the answer, which is an imaginary number, just simplify the bracketed terms.
anonymous
  • anonymous
How do I simplify bracketed terms
kropot72
  • kropot72
Multiply the square root of 5 by the square root of 5.
Teddyiswatshecallsme
  • Teddyiswatshecallsme
I think its. \[\sqrt{-5} {\times} \sqrt{5} = \sqrt[4]{-25}\]
j2lie
  • j2lie
That makes more sense. @Teddyiswatshecallsme
anonymous
  • anonymous
Im confused now.
kropot72
  • kropot72
\[\large (\sqrt{5}\times \sqrt{5})i=5i\]
anonymous
  • anonymous
Its -5
kropot72
  • kropot72
The correct result must be an imaginary number.
anonymous
  • anonymous
So is @Teddyiswatshecallsme right or @kropot72
kropot72
  • kropot72
Has anybody given Teddy a medal?
anonymous
  • anonymous
No
kropot72
  • kropot72
@basketball305 Who will judge which is the correct answer?
zzr0ck3r
  • zzr0ck3r
@kropot72 is absolutely correct. Trust the person that shows there work, because if they are wrong you can find it in their work \(\sqrt{5}\sqrt{-5}=\sqrt{5}\sqrt{-1*5}=\sqrt{5}\sqrt{5}\sqrt{-1}=5\sqrt{-1}=5i\)
zzr0ck3r
  • zzr0ck3r
their*
anonymous
  • anonymous
|dw:1441246950614:dw|
kropot72
  • kropot72
@zzr0ck3r Thank you for confirmation :)

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