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anonymous

  • one year ago

square root of -5 multiplied by square root of 5

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  1. j2lie
    • one year ago
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    -5 and 5 does not have a perfect square root.

  2. anonymous
    • one year ago
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    \[\sqrt{-5} \times \sqrt{5}\]

  3. anonymous
    • one year ago
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    So what does that mean?

  4. j2lie
    • one year ago
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    The square root is between 2 and 3.

  5. anonymous
    • one year ago
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    I dont get it

  6. j2lie
    • one year ago
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    the square root is either 2.5 or below.

  7. kropot72
    • one year ago
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    \[\large \sqrt{-1}=i\] The square root of negative one is the imaginary number i. Factorising the square root of negative 5 we get: \[\large \sqrt{-5}\times \sqrt{5}=(\sqrt{5}\times \sqrt{5})i\]

  8. kropot72
    • one year ago
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    The get the answer, which is an imaginary number, just simplify the bracketed terms.

  9. anonymous
    • one year ago
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    How do I simplify bracketed terms

  10. kropot72
    • one year ago
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    Multiply the square root of 5 by the square root of 5.

  11. Teddyiswatshecallsme
    • one year ago
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    I think its. \[\sqrt{-5} {\times} \sqrt{5} = \sqrt[4]{-25}\]

  12. j2lie
    • one year ago
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    That makes more sense. @Teddyiswatshecallsme

  13. anonymous
    • one year ago
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    Im confused now.

  14. kropot72
    • one year ago
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    \[\large (\sqrt{5}\times \sqrt{5})i=5i\]

  15. anonymous
    • one year ago
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    Its -5

  16. kropot72
    • one year ago
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    The correct result must be an imaginary number.

  17. anonymous
    • one year ago
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    So is @Teddyiswatshecallsme right or @kropot72

  18. kropot72
    • one year ago
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    Has anybody given Teddy a medal?

  19. anonymous
    • one year ago
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    No

  20. kropot72
    • one year ago
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    @basketball305 Who will judge which is the correct answer?

  21. zzr0ck3r
    • one year ago
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    @kropot72 is absolutely correct. Trust the person that shows there work, because if they are wrong you can find it in their work \(\sqrt{5}\sqrt{-5}=\sqrt{5}\sqrt{-1*5}=\sqrt{5}\sqrt{5}\sqrt{-1}=5\sqrt{-1}=5i\)

  22. zzr0ck3r
    • one year ago
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    their*

  23. anonymous
    • one year ago
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    |dw:1441246950614:dw|

  24. kropot72
    • one year ago
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    @zzr0ck3r Thank you for confirmation :)

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