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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    \[\lim x->4 =(\sqrt{x+5}-3)/x-4\]

  2. anonymous
    • one year ago
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    Any help.

  3. misty1212
    • one year ago
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    HI!!

  4. misty1212
    • one year ago
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    you do get \(\frac{0}{0}\) when you plug in right?

  5. misty1212
    • one year ago
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    gimmick here is to multiply numerator and denominator by the conjugate of the numerator to rationalize it do you know what i am talking about?

  6. theopenstudyowl
    • one year ago
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    Rationalize the numerator....

  7. anonymous
    • one year ago
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    \[\frac{\sqrt{x+5}-3}{x-4}\times \frac{\sqrt{x+5}+3}{\sqrt{x+5}+3}\] ois what @misty1212 is telling you to do

  8. anonymous
    • one year ago
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    leave the denominator in factored form just multiply up top

  9. misty1212
    • one year ago
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    yeah that you good from there?

  10. anonymous
    • one year ago
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    Oh, thanks!

  11. anonymous
    • one year ago
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    I would always FOIL the denominator too, which was my issue.

  12. misty1212
    • one year ago
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    \[\color\magenta\heartsuit\]

  13. anonymous
    • one year ago
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    oh no don't do that you should expect the \(x-4\) to cancel, do don't multiply out

  14. anonymous
    • one year ago
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    Yeah, I saw it just now, that makes sense, thanks again! I got 1/6 just to confirm.

  15. misty1212
    • one year ago
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    that looks good

  16. anonymous
    • one year ago
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    Alright thanks again guys!

  17. misty1212
    • one year ago
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    lol guess i cam a guy now

  18. anonymous
    • one year ago
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    yw

  19. anonymous
    • one year ago
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    yeah you look like a guy!

  20. anonymous
    • one year ago
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    Oh, I was referring to both of you haha

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spraguer (Moderator)
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