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\[(34+18\times 2)-(5\times 2+7)\]is a better start
then maybe a calclulator
actually get none of the above could there be a typo there?
nope that's the choices
can you post a screenshot of the question?
maybe i read "18.q" wrong not really clear there
yea i'll get a screenshot hold on
why is this same question posted again?
Because my teacher gave me a second chance at this question and he said if I couldn't figure it out after five tries he said I can ask for help so I am
Ah 5 to the power of q, that means the following \[5^2 = (5)(5) =25\]
nothing like the equation editor
but we can't help you if the question is not clear.
Please use "^" to indicate to the power of next time :)
i just posted a file showing the test look at it to understand it
\[(34+18\times 2)-(5^ 2+7)\]
i guess you are supposed to be practising the "order 'o operations" right?
you know what to do first?
yup now starting Algebra and haha no my weakest link in school is math I barley passed Math last year so this is beyond me I better understand History then i do math
i.e. compute \(5^2=5\times 5\) don't think too hard here
what do you get?
hold on had to get a drink
yeah i need one too maybe some bulleit rye
did you manage to compute \(5\times 5\) yet?
care to share it with the class?
so now \[(34+18\times 2)-(5^ 2+7)=(34+18\times 2)-(25+7)\]
now lets do the multiplication \(18\times 2=?\)
ok so now we are at \[(34+36)-(25+7)\] add in each parentheses what do you get?
(34 + 36 = 70) (25 + 7 = 32) all together = 102
there is no such mathematical operation as "all together" is there?
you should be looking at \[70-32\]
i'm tired so I'm really not paying attention to what I type
then go to bed and do this arithmetic some other day
i can't I have to have this submitted by 11:30 tonight or I fail it