1. If Q=2, Evaluate (34 + 18. q) - (5q + 7)
A. 38
B. 79
C. 31
D. 21

- supercait10

1. If Q=2, Evaluate (34 + 18. q) - (5q + 7)
A. 38
B. 79
C. 31
D. 21

- chestercat

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- anonymous

\[(34+18\times 2)-(5\times 2+7)\]is a better start

- anonymous

then maybe a calclulator

- anonymous

actually get none of the above
could there be a typo there?

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## More answers

- supercait10

nope that's the choices

- anonymous

can you post a screenshot of the question?

- anonymous

maybe i read "18.q" wrong
not really clear there

- supercait10

yea i'll get a screenshot hold on

- anonymous

ok

- supercait10

the last one

##### 1 Attachment

- triciaal

why is this same question posted again?

- supercait10

Because my teacher gave me a second chance at this question and he said if I couldn't figure it out after five tries he said I can ask for help so I am

- anonymous

Ah 5 to the power of q, that means the following \[5^2 = (5)(5) =25\]

- anonymous

oooh !!

- anonymous

nothing like the equation editor

- triciaal

but we can't help you if the question is not clear.

- anonymous

Please use "^" to indicate to the power of next time :)

- supercait10

i just posted a file showing the test look at it to understand it

- anonymous

\[(34+18\times 2)-(5^ 2+7)\]

- anonymous

i guess you are supposed to be practising the "order 'o operations" right?

- anonymous

you know what to do first?

- supercait10

yup now starting Algebra and haha no my weakest link in school is math I barley passed Math last year so this is beyond me I better understand History then i do math

- anonymous

square first

- anonymous

i.e. compute \(5^2=5\times 5\) don't think too hard here

- anonymous

what do you get?

- supercait10

hold on had to get a drink

- anonymous

yeah i need one too
maybe some bulleit rye

- supercait10

lol maybe

- anonymous

did you manage to compute \(5\times 5\) yet?

- supercait10

yea

- anonymous

care to share it with the class?

- supercait10

yea

- anonymous

...

- supercait10

25

- anonymous

whew

- anonymous

so now \[(34+18\times 2)-(5^ 2+7)=(34+18\times 2)-(25+7)\]

- anonymous

now lets do the multiplication \(18\times 2=?\)

- supercait10

36

- anonymous

ok so now we are at
\[(34+36)-(25+7)\] add in each parentheses
what do you get?

- supercait10

(34 + 36 = 70) (25 + 7 = 32) all together = 102

- anonymous

there is no such mathematical operation as "all together" is there?

- anonymous

you should be looking at \[70-32\]

- supercait10

i'm tired so I'm really not paying attention to what I type

- anonymous

then go to bed and do this arithmetic some other day

- supercait10

i can't I have to have this submitted by 11:30 tonight or I fail it

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