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anonymous
 one year ago
Will medal and fan!
I need help on a K12 Math assessment it's 9:00 pm and Ive been trying to complete this all day :( please help here is picture of problem
http://i.imgur.com/A9RtbOe.jpg
anonymous
 one year ago
Will medal and fan! I need help on a K12 Math assessment it's 9:00 pm and Ive been trying to complete this all day :( please help here is picture of problem http://i.imgur.com/A9RtbOe.jpg

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if anyone could help me with this that would be great Ive done it 2 times and got bad grades both times

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0multiply both sides by 5 to clear the annoying fraction

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the parentheses on the left side and on the right side?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you should get \[2x15+3x=21\tfrac{1}{4}\] now at least the fractions on the left are gone

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now combine like terms on the left, i .e. add \(2x+3x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so now we are at \[5x15=21\tfrac{1}{4}\] add 15

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry if my spelling or grammer is a bit off im really tired right now :

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what are we adding 15 to

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no one here is a grammarian (least of all me)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the math teaches say "add it to both sides" but you really add it to the right to get rid of the 15 on the left

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you need to add the 15 to the right as well

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[5x=36\tfrac{1}{4}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah that i hate mixed numbers now divide by 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0divide what by 5 sorry again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you have \[5x=36\tfrac{1}{4}\] and you want \[x=\text{sommat}\] to get there you have to divide both sides by 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i.e. \[x=36\tfrac{1}{4}\div 5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yw you got more? i noticed you were on a deadline

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That was actually the last question of the assessment i can tell you how i did tho

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0saved the best for last i guess

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it a placement test?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0k12 is a bit wierd you take a small test to see if you learned everything correctly from the lesson before it after you go through the lesson.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0By the way I got 5/5 :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is good! guess you got the first 4 on your own yw
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